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2 years ago

35 + z =500 help me

Mathematics

2 answers:

RideAnS [48]2 years ago

8 0

Answer:

465

Step-by-step:

500-35=465

ozzi2 years ago

5 0

465

You get this by taking 500 and subtracting 35. Then to check you add your answer to 35 and see if it adds up which it does

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In the last year, a total of 2727 earthquakes occurred in the country. Of these, 85.3 % were minor tremors with magnitudes of

Komok [63]

Answer:

Minor earthquakes occurred in the country in the last year were 2326.

Step-by-step explanation:

Given:

In the last year, a total of 2727 earthquakes occurred in the country.

Of these, 85.3 % were minor tremors with magnitudes of 3.9 or less on the Richter scale.

Now, to find the minor earthquakes occured in the country last year.

Total earthquakes occurred in the country = 2727.

The percent of minor earthquakes = 85.3%.

Now, to get the number of minor earthquakes:

85.3% of 2727.

$=\frac{85.3}{100} \times 2727.$

$=\frac{232613.1}{100}$

$=2326.131$

The number of minor earthquakes nearest whole number = 2326.

Therefore, minor earthquakes occurred in the country in the last year were 2326.

3 0

2 years ago

18/50 in the simplest form

erik [133]

The simplest form of the fraction is 9/25

4 0

2 years ago

Please someone answer quick I need this for tomorrow for school and I'm not done pls tell me the right answer thanks

nikklg [1K]

answer to a) 18,36,,54

answer to b) 30,60,90

answer to c)20,40,60

answer to d)168,336,504

7 0

3 years ago

Read 2 more answers

Solve for u. U/-1 +-4=-1 U =

kherson [118]

Answer:

U = -3

Step-by-step explanation:

U/-1 +-4=-1

Add 4 to each side

U/-1 +-4+4=-1+4

U / -1 = 3

Multiply each side by -1

U / -1 * -1 = 3* -1

U = -3

3 0

2 years ago

Solve for x:a(a²+b²)x²+b²x-a

m_a_m_a [10]

Answer:

x = a/(a² + b²) or x = -1/a

Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

Use the quadratic equation formula:

$x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =\dfrac{-b\pm\sqrt{D}}{2a}$

1. Evaluate the discriminant D

D = b² - 4ac = b⁴ - 4a(a² + b²)(-a) = b⁴ + 4a⁴ + 4a²b² = (b² + 2a²)²

2. Solve for x

$\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}$

$\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}$

5 0

3 years ago