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TiliK225 [7]
3 years ago
15

How many different 5-digit pins are there where none of the digits are repeated?

Mathematics
1 answer:
vazorg [7]3 years ago
7 0
<span>With no digit being repeated: 10*9*8*7*6= 30,240</span>
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-3 + 8n = -5<br> what is n?
nirvana33 [79]
Click link above for the answer
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3 years ago
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Write an equation for the perpendicular bisector of the line segment joining the two points.
Leona [35]
Points (1, 7)  and  (-3, 2)

Slope for a line between (x₁, y₁) and (x₂, y₂) , m = (y₂ -y₁) / (x₂- x₁)

The slope for the line joining the two points =  (2 - 7) / (-3 - 1) = -5/-4

Slope = 5/4

Hence the perpendicular bisector would have a slope of -1/(5/4) = -4/5

By condition of perpendicularity

For points (1, 7)  and  (-3, 2),

Formula for midpoints for (x₁, y₁) and (x₂, y₂) is ((x₁ +x₂)/2 , (y₁+ y₂)/2)

Midpoint for (1, 7)  and  (-3, 2) = ((1+ -3)/2 , (7+2)/2) = (-2/2, 9/2)

= (-1, 9/2)

Since the slope of perpendicular bisector is -4/5 and passes through the midpoint (-1, 9/2)

Equation  y - y₁ = m (x - x₁)

                y - 9/2 = (-4/5) (x - -1)
           
                y - 9/2 = (-4/5)(x + 1)

               5(y - 9/2) = -4(x + 1)

               5y - 45/2 = -4x - 4

                 5y =  -4x - 4 + 45/2
           
                5y + 4x = 45/2 - 4

                  5y + 4x = 22  1/2  - 4 =  18 1/2

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                  10y + 8x = 37

The equation of the line to perpendicular bisector is 10y + 8x = 37
7 0
4 years ago
10. A movie theater advertises that a family of two adults, one student, and one child between the ages of 3
BlackZzzverrR [31]

Answer:

Students ticket = $4

Child ticket = $1

Adult ticket = $5

Step-by-step explanation:

Let the price of the student ticket be $x and the price of a child ticket be $y.  An adult ticket costs as much as the combined cost of a student ticket and a child ticket, so the price of one adult ticket is $(x+y).

1. A movie theater advertises that a family of two adults, one student, and one child between the ages of 3 and 8 can attend a movie for $15. Then

2(x+y)+x+y=15

2. If you purchase 1 adult ticket, 4 student tickets, and 2 child tickets for $23, then

(x+y)+4x+2y=23

Now, solve the system of two equations:

\left\{\begin{array}{l}2(x+y)+x+y=15\\ \\(x+y)+4x+2y=23\end{array}\right.\Rightarrow \left\{\begin{array}{l}3(x+y)=15\\ \\5x+3y=23\end{array}\right.\\ \\\left\{\begin{array}{l}x+y=5\\ \\5x+3y=23\end{array}\right.\\ \\\left\{\begin{array}{l}y=5-x\\ \\5x+3(5-x)=23\end{array}\right.

Solve the last equation

5x+15-3x=23\\ \\2x=23-15\\ \\2x=8\\ \\x=4\\ \\y=5-x=5-4=1

Students ticket = $4

Child ticket = $1

Adult ticket = $5

8 0
3 years ago
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Dennis_Churaev [7]
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Alexeev081 [22]
Plug h = 3 and g = 27 into the expression:

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