All categories

3 years ago

How many different 5-digit pins are there where none of the digits are repeated?

Mathematics

1 answer:

vazorg [7]3 years ago

7 0

<span>With no digit being repeated: 10*9*8*7*6= 30,240</span>

You might be interested in

I need to a paint a spherical storage tank in the pool. it has a radius of 8 feet and the paint cans i brought will cover 75 squ

Alexxandr [17]

<h3>Answer: 11 cans</h3>

======================================================

Explanation:

SA = surface area of the sphere

SA = 4*pi*r^2

SA = 4*pi*8^2

SA = 804.247719

The surface area is roughly 804.247719 sq ft.

I used the calculator's stored version of pi to get the most accuracy possible.

Since 1 paint can covers 75 sq ft, divide that surface area over 75 to find out how many cans you need.

804.247719/75 = 10.72330292

Round up to the nearest integer to get 11

You'll have leftover paint, but it's better to go over the goal than come up short.

8 0

3 years ago

Sita saves Rs. 1 today, Rs. 2 the next day, Rs. 4 the succeeding day and so on (each saving being twice of the preceding one). W

Alenkinab [10]

Answer:

Rs. 32767

Step-by-step explanation:

Because the amount is doubling every day, we can use the expression 1*2^15-1 because there is 1 to start with. Also cool trick! if you need to do 2^1+2^2+2^3+....+2^x, it will be equal to 2^(x+1)-1. So:

2^15-1

32768-1

32767

3 0

2 years ago

20.) A=49.23 degrees, c=54.8Solve the right triangle. Express angles in decimal degrees.

vivado [14]

$\begin{gathered} a=41.50 \\ b=35.78 \\ B=40.76\text{ \degree} \\ \end{gathered}$

Explanation

Step 1

a) let

$\begin{gathered} A=49.23\text{ \degree} \\ c=54.8\text{ \degree} \end{gathered}$

b) b value

to find the measure of side b we can use cosine function

$\begin{gathered} cos\theta=\frac{adjacent\text{ side}}{hypotenuse} \\ replace \\ cos\text{ 49.23=}\frac{b}{54.8} \\ b=54.8*cos49.23 \\ b=35.78 \end{gathered}$

c) angle B

to find the measure of Angle B we can use sine function

$\begin{gathered} sin\theta=\frac{opposite\text{ side}}{hypotenuse} \\ replace \\ sin\text{ B=}\frac{35.78}{54.8} \\ sin\text{ B= 0.65}\Rightarrow inverse\text{ function to isolate B} \\ B=\sin^{-1}(0.65) \\ B=40.76 \end{gathered}$

d) side a

$\begin{gathered} sin\theta=\frac{opposite\text{ side}}{hypotenuse} \\ sin\text{ A=}\frac{a}{c}=\frac{\placeholder{⬚}}{\placeholder{⬚}} \\ sin\text{ 49.23=}\frac{a}{54.8} \\ multiply\text{ both sides by 54.8} \\ 54.8s\imaginaryI n\text{49.23=}\frac{a}{54.8}*54.8 \\ 41.50=a \end{gathered}$

so, the answer is

$\begin{gathered} a=41.50 \\ b=35.78 \\ B=40.76\text{ \degree} \\ \end{gathered}$

I hope this helps you