The total number of handshakes was 234.
- The first man shook hands with 12 other men.
- The second man shakes hands with 11 other men, as he had already shaken hands with the first man.
- Like-wise, the last man does not need to shake hands again as every man has already shaken hands with him in their respective turns.
- The number of handshakes among men is 0 + 1 + 2 + … + 12.
- The sum of "n" natural numbers = (n)(n+1)/2
- The number of handshakes among men is 12(13)/2.
- The number of handshakes among men is 78.
- Each man shakes hands with every woman except his spouse.
- Each man shakes hands with 12 other women.
- The number of handshakes between men and women is 13*12.
- The number of handshakes between men and women is 156.
- The total number of handshakes is 78 + 156.
- The total number of handshakes is 234.
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Answer:
B
Step-by-step explanation:
You can find the percentage by dividing 8/160 and then multiply by 100 so that's 5%
Step-by-step explanation:
p = 0.1, q = 0.9, n = 7
a) Use complementary probability.
P(at least 1) = 1 − P(0)
P(at least 1) = 1 − (0.9)⁷
P(at least 1) = 0.522
b) Use binomial probability.
P = nCr pʳ qⁿ⁻ʳ
P(3) = ₇C₃ (0.1)³ (0.9)⁴
P(3) = 0.023
Step-by-step explanation:
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