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olga2289 [7]
1 year ago
14

A bat descends at a steady rate from 45.625 feet above the ground to a spot 36.5 above the ground in 3.75 seconds.

Mathematics
2 answers:
Georgia [21]1 year ago
8 0

Answer:  2.43

Step-by-step explanation:

FrozenT [24]1 year ago
4 0
Answer 2.43

Explanation: I did the math but seriously if you want a explanation comment and i’ll explain the process
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Change 33 feet to yards
tamaranim1 [39]

Answer: 11 yds

Step-by-step explanation: 1 yd=3 ft

7 0
2 years ago
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Form the intersection for the following sets. M = { } N = {6, 7, 8, 9, 10} M ∩ N = {0, 6, 7, 8, 9, 10} {Ø, 6, 7, 8, 9, 10} {6, 7
antoniya [11.8K]
Answer: The empty set { } which can be represented by the symbol \varnothing

Why is this the answer? Because there is nothing inside set M. Set M is itself the empty set. Intersecting the empty set with any other set leads to the empty set again. 
7 0
3 years ago
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The Target heart rate for fit person of age a exercising at p percent of his or her heart rate is determined by the expression 1
natita [175]

Answer: 9p - 1.5a

Step-by-step explanation:

Your maximum heart rate is about 220 minus your age. But it varies base on age category.

Target heart rate during moderate intensity activities is about 50-70% of maximum heart rate.

According to the question;

Target heart rate for

women = 1/2p(418-4a)

= 209p - 2a ....... (1)

men = 1/2p(400-a)

= 200p - 0.5a .......(2)

To find the difference between the target heart rates for a fit woman and a fit man, take equation 1 from equation 2

(209p - 2a) - (200p - 0.5a)

209p - 2a - 200p + 0.5a

9p -1.5a

7 0
3 years ago
Simplify. 7√32−6√72 Enter your answer, in simplest radical form, in the box.
Whitepunk [10]

Answer-

-8\sqrt2

Step-by-step explanation:

7 0
3 years ago
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What is the value of ​2×[34−5×(3+1)]​ ?
spayn [35]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{28}}}}}

Step-by-step explanation:

Use BODMAS rule :

Bracket , Of , Division , Multiplication , Addition , Subtraction

\sf{2 \times [ 34 - 5 \times (3 + 1) ] }

Add the numbers : 3 and 1

\dashrightarrow{ \sf{2 \times [ 34 - 5 \times 4 ] }}

Multiply the numbers : 5 and 4

\dashrightarrow{ \sf{2 \times [ 34  - 20 \: ]  }}

Subtract 20 from 34

\dashrightarrow{ \sf{2 \times 14}}

Multiply the numbers : 2 and 14

\dashrightarrow{ \sf{28}}

Hope I helped!

Best regards! :D

4 0
3 years ago
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