Question

Solve for x: |x − 2| + 10 = 12

Answer 1

Answer:

Option A is correct.

Values of x :

x = 0 and x  =4

Step-by-step explanation:

Absolute function states that contains an algebraic expression within absolute value symbols i,e

$|x| = \left\{\begin{matrix}x & if x>0 \\ 0 & if x = 0\\ -x & if x< 0 \end{matrix}\right.$

Given that: $|x-2|+10=12$              .....[1]

solve for x;

Subtract 10 from both sides in equation [1] we get;

$|x-2|+10-10=12-10$  

Simplify:

$|x-2|=2$  

By definition of Absolute;

(x-2) = 2 and -(x-2) = 2

or

x-2 =2   and x -2 = -2

we have;

x = 2+2  and  x= -2+2

x = 4   and x = 0

Therefore, the value of x are 4 and 0.

Answer 2

|x − 2| + 10 = 12

|x − 2| =2
x-2=+-2
x-2=2 and x-2=-2
x=4 and x=0