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ludmilkaskok [199]

3 years ago

15

Write a phythagoras triplet whose one is no. 17

2 answers:

Bezzdna [24]3 years ago

8 0

<h2>8, 15, 17</h2>

$2m, \: m^2-1, \: m^2+1$

17 can be expressed as $16+1 = 4^2+1$

$m=4$

$2(4), \: (4)^2-1, \: (4)^2+1$

$8, 16-1, 16+1$

$8,15,17$

hjlf3 years ago

3 0

So the Pythagorean triplet is 8,15and 17

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What is the result when 8x^3+16x2+24x+27/2x+3

Pavlova-9 [17]

The answer is 4x^2+2x+9

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3 years ago

Calculate the value of the sample variance. Round your answer to one decimal place. 9_5,9_5,2,9_5

Ugo [173]

Answer:

$s^2 = 0.01$

Step-by-step explanation:

Given

Values: 9/5, 9/5, 2, 9/5

Required

Calculate the sample variance

Sample variance is calculated using:

$s^2 = \frac{\sum (x_i - \overline x)^2}{n - 1}$

First, we calculate the mean

$\overline x = \frac{\sum x}{n}$

$\overline x = \frac{9/5 + 9/5 + 2 + 9/5}{4}$

$\overline x = \frac{7.4}{4}$

$\overline x = 1.85$

$s^2 = \frac{\sum (x_i - \overline x)^2}{n - 1}$ becomes

$s^2 = \frac{(9/5 - 1.85)^2+(9/5 - 1.85)^2+(2 - 1.85)^2+(9/5 - 1.85)^2}{4 - 1}$

$s^2 = \frac{(-0.05)^2+(-0.05)^2+(0.15)^2+(-0.05)^2}{4 - 1}$

$s^2 = \frac{0.0025+0.0025+0.0225+0.0025}{3}$

$s^2 = \frac{0.03}{3}$

$s^2 = 0.01$

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5 0

2 years ago

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Neko [114]

Answer:

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Step-by-step explanation

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2 years ago

The volume of a volleyball is about 288 cubic inches. what is the radius of the volleyball, to the nearest tenth of an inch? use

Len [333]

Answer:

The radius of the volleyball is 8.3 inches

Step-by-step explanation:

Given

$r = \sqrt{\frac{3v}{4\pi}}$

$v = 288$

Required

Determine the value of r

To do this, we simply substitute 288 for v and 3.14 for π in the given equation.

This gives

$r = \sqrt{\frac{3v}{4\pi}}$

$r = \sqrt{\frac{3 * 288}{4 * 3.14}}$

$r = \sqrt{\frac{864}{12.56}}$

$r = \sqrt{68.7898089172}$

$r = 8.29396219651$

$r = 8.3\ inch$ (Approximated)

Hence;

<em>The radius of the volleyball is 8.3 inches</em>

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2 years ago

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Step-by-step explanation:

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2 years ago

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