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WITCHER [35]
2 years ago
15

How do you solve break even problems?

Mathematics
1 answer:
Mandarinka [93]2 years ago
8 0
A break even problem is found when you calculate starting a buisieness
so lets ssay you have to buy 3 coppy machines and each machine costs 2000 dollars,
the people who want to use your coppy machines have to pay $0.40 per page
so you have spent 6000 dollars already
when you break even, it is when your earnings equals your expenditure (how much you earned equals how much you paid)
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If an arithmetic sequence
goblinko [34]

Answer:

a₄ = 12

Step-by-step explanation:

To obtain the terms in the sequence add 2 to the previous term, that is

a₂ = a₁ + 2 = 6 + 2 = 8

a₃ = a₂ + 2 = 8 + 2 = 10

a₄ = a₃ + 2 = 10 + 2 = 12

5 0
2 years ago
The quadratic x? - x = 2 has two solutions. What<br> is the larger of the two solutions?
chubhunter [2.5K]
I believe the 2 is the largest
5 0
3 years ago
The sum of two numbers is 87, and one number is eleven more than the other. fing the number​
lara31 [8.8K]

Answer: 49 and 38

Step-by-step explanation:

I did trial and error

38+11=49

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4 0
3 years ago
A climber on Mt Everest is 6000 meters from the start of his trail and at elevation 8000 meters above sea level. At x meters fro
sergeinik [125]

Answer:

h'(x) = 0.6 and Δx = 1 and 2

h(6001) = h(6000) + h'(6000)(1) = 8000 +0.6 = 8,000.6

h(6002) = h(6000) + h'(6000)(2) = 8000 + 0.6 (2) =8000 +1.2 = 8001.2

Explanation below:

Step-by-step explanation:

Based on the information given we have that when the climber is 6000 meters from the start, his elevation is 8000 meters above sea level.

We know that the function for elevation is given by h(x) where x is the number of meters from the start.

Therefore, h(6000) = 8000.

We also know that the derivative of a function tells us the reason of change at some point (or how fast a function is changing near that point). For this problem we have that h'(x) = 0.6. (<u>meaning that the elevation increases in 0.6 meters for every meter they hike further nearby the 6000 meters</u>)

We need to use the derivative at a point to estimate values of the function at nearby points

We're going to use h'(x)= 0.6. Δx= 1

h(6001) = h(6000) + h'(6000)(1) = 8000 +0.6 = 8,000.6

Therefore h (6001) = 8,000.6

Now for h'(x)= 0.6. Δx= 1

h(6002) = h(6000) + h'(6000)(2) = 8000 + 0.6 (2) =8000 +1.2 = 8001.2

Therefore h(6002) = 8001.2

6 0
3 years ago
When 60% of a number is added to the number, the result is 192. What is the number? Show your work.​
Natali [406]
Let the original number be
x

x
×
160
100
=
192
. This indicates an increase of 60%



x
=
192
×
100
160

x
=
120
7 0
3 years ago
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