0<4x + 8<12 BADDA-BING-BADDA-BOOM!!! :-)
Answer:
- time = 1second
- maximum height = 16m
Step-by-step explanation:
Given the height of a pumpkin t seconds after it is launched from a catapult modelled by the equation
f(t)=-16t²+32t... (1)
The pumpkin reaches its maximum height when the velocity is zero.
Velocity = {d(f(x)}/dt = -32t+32
Since v = 0m/s (at maximum height)
-32t+32 = 0
-32t = -32
t = -32/-32
t = 1sec
The pumpkin reaches its maximum height after 1second.
Maximum height of the pumpkin is gotten by substituting t = 1sec into equation (1)
f(1) = -16(1)²+32(1)
f(1) = -16+32
f(1) = 16m
The maximum height of the pumpkin is 16m
Answer:
The answer is C
Step-by-step explanation:
Let's solve your equation step-by-step.
4(x−2)=6x+18
Step 1: Simplify both sides of the equation.
4(x−2)=6x+18
(4)(x)+(4)(−2)=6x+18(Distribute)
4x+−8=6x+18
4x−8=6x+18
Step 2: Subtract 6x from both sides.
4x−8−6x=6x+18−6x
−2x−8=18
Step 3: Add 8 to both sides.
−2x−8+8=18+8
−2x=26
Step 4: Divide both sides by -2.
−2x/−2=26/−2
x=−13
Answer:
x=−13
Use distributie property which is
a(b+c)=ab+ac
therefor
6x(x-4)=6x^2-24x
distribute the negative 1 infroont of the (9x-1)
-1(9x-1)=-9x+1
now we have
6x^2-24x-16x^2-9x+1
gropu like terms
6x^2-16x^2-24x-9x+1
add like terms
-10x^2-33x+1 is simplest form
