The lines on a basketball form a half circle at the free throw line. Use the picture to determine the area of the half circle. Round your answer to the nearest tenth.
The exact value is
<span>sin<span>(arccos<span>(<span>3/4</span>)</span>)</span></span>The equation for cosine is <span>cos<span>(A)</span>=<span>AdjacentHypotenuse</span></span>. The inside trig function is <span>arccos<span>(<span>3/4</span>)</span></span>, which means <span>cos<span>(A)</span>=<span>3/4</span></span>. Comparing <span>cos<span>(A)</span>=<span>AdjacentHypotenuse</span></span> with <span>cos<span>(A)</span>=<span>3/4</span></span>, find <span>Adjacent=3</span> and <span>Hypotenuse=4</span>. Then, using the pythagorean theorem, find <span>Opposite=<span>√7</span></span>.<span>Adjacent=3</span><span>Opposite=<span>√7</span></span><span>Hypotenuse=4</span>Substitute in the known variables for the equation <span>sin<span>(A)</span>=<span>OppositeHypotenuse</span></span>.<span>sin<span>(A)</span>=<span><span>√7</span> over 4</span></span>Simplify.<span><span>√7</span><span> over 4</span></span>
Answer:
83.2 cm^2
Step-by-step explanation:
To solve this we're going to find the area of the bigger triangle (the shaded and unshaded parts together) and then the area of the smaller triangle (the unshaded part) and then subtract that from the area of the bigger triangle. We're going to use the equation: Area=1/2 x base x height. So the base of the big triangle is 16, and the height is (10.4+8.6 = 19). Put into the equation this looks like this: Area=1/2 x 16 x 19, so by multiplying we find that the area is 152 cm^2. Next we find the small triangle's area, Area=1/2 x 16 x 8.6, so the area is 68.8. Then to find the area of the shaded part, we subtract the unshaded area (68.8) from the whole area (152), 152-68.8=83.2.
If the equation is let's say 3x+ 7 +4x to combine like terms, you would take 3x and 4x since they both have x. You wouldn't take the 7 since it doesn't have and x like the other numbers. 3x +4x = 7x so your new equation would be 7x + 7.
