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fiasKO [112]
3 years ago
6

PLZ HELP WITH THIS QUESTION !!!!!!!!!

Mathematics
1 answer:
____ [38]3 years ago
8 0

Answer:

I believe the answer is B

Step-by-step explanation:

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\huge\boxed{y-5&=-\frac{1}{3}(x+9)}

First, we'll find the slope of the new line. The first line has a slope of 3. Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by -1) to get -\frac{1}{3} for the new slope.

Then, we'll use the point-slope form to make the new equation, where m is the slope and (x_1,y_1) is a point on the line:

\begin{aligned}y-y_1&=m(x-x_1)\\y-5&=-\frac{1}{3}(x-(-9))\\y-5&=-\frac{1}{3}(x+9)\end{aligned}

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(-6,-4)

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A reflection over the x-axis changes the y variable

(x,y)--->(x,-y)

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39 >-39 ,   |39| = |-39|    there you go
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