Answer:
Area of nail's head = 28.26 millimeter² (Approx.)
Step-by-step explanation:
Given:
Head of nail is circular
Diameter of nail's head = 6 millimeter
Find:
Area of nail's head
Computation:
Radius of nail's head = Diameter / 2
Radius of nail's head = 6 / 2
Radius of nail's head = 3 millimeter
Area of circle = πr²
Area of nail's head = πr²
Area of nail's head = (22/7)(3)²
Area of nail's head = (22/7)(9)
Area of nail's head = (3.14)(9)
Area of nail's head = 28.26 millimeter² (Approx.)
<h3>To find the product of 42.12 and 10^3, move the decimal point in 42.12 3 places to the right because 10^3 has 3 zeros</h3>
<em><u>Solution:</u></em>
Given that,

Which means,

Here, the exponent of 10 is positive ( which is 3)
When the exponent is positive, we have to move the decimal point to right
When you multiply a number by a power of 10, ( 10!, 10^2, and so on ) move the decimal point of the number to the right the same number of places as the number of zeros in the power of 10
Here, exponent is 3 , therefore move the decimal point right 3 places in 42.12
Therefore,

IMproper fraction is what you need to covert it 2 cuz u multiply then add and u'll get it
Answer:
AKPOS/ACGF = 28√3 -48 ≈ 0.497423
Step-by-step explanation:
Let's assume the square is a unit square. Then the height of the triangle is ...
1 +(√3)/2 = h
and half the base of the triangle is ...
h/√3 = (√3)/3 +1/2 = b/2
The area of the triangle is the product of these:
A = (1/2)bh
= (2 +√3)/2 × (3 +2√3)/6
= (6 +3√3 +4√3 +6)/12 = (12 +7√3)/12
So, the ratio of the area of the square to that of the triangle is the inverse of this, or ...
(square area)/(triangle area) = 12/(12+7√3)
(square area)/(triangle area) = 28√3 -48