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zloy xaker [14]
3 years ago
6

What is 3/22 step by step?

Mathematics
1 answer:
Anna11 [10]3 years ago
7 0

Answer:

Step-by-step explanation:

First you would see how many times 3 would go into 22 and it would be 7 with a remainder of 1. Then you would do 7 times 3 which is 21. And 22 minus 21 is 1. Then your answer would be 7 with a remainder of 1. If you don't want a remainder, and you want a decimal then you would add a decimal point after the 22 and then add a 0. You would bring down the zero and then  the remainder of one would be 10 then you would see how much 3 goes into 10, and it only goes 3 times. Your answer would be 7.3 with a remainder of 1, If you keep going you will see it becomes a repeating decimal. *Hope it helped*

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HELP PLEASE ASAP..........
Usimov [2.4K]
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6 0
3 years ago
Enter the simplified form of the complex fraction in the box. Assume no denominator equals zero.
Olenka [21]

Answer:

\frac{(9-x)}{3x}

Step-by-step explanation:

we have

\frac{\frac{2}{x-3}-\frac{3}{x}}{\frac{3}{x-3}}

step 1

Solve the numerator of the quotient

\frac{2}{x-3}-\frac{3}{x}=\frac{2x-3(x-3)}{(x-3)x}=\frac{2x-3x+9}{(x-3)x}=\frac{9-x}{(x-3)x}

step 2

substitute in the original expression

\frac{\frac{9-x}{(x-3)x}}{\frac{3}{x-3}}

\frac{(x-3)(9-x)}{3x(x-3)}

step 3

simplify

\frac{(9-x)}{3x}

5 0
2 years ago
What is the solution of this system of linear equations? 3y = 3 y equals StartFraction 3 over 2 EndFraction x plus 6.X + 6 y – S
Scrat [10]

Answer:

(0,6)

Step-by-step explanation:

The given system of equations is

y =  \frac{3}{2}x + 6

and

\frac{1}{2}y -  \frac{1}{4}x = 3

We substitute the first equation into the second equation to get:

\frac{1}{2} ( \frac{3}{2}x + 6) -  \frac{1}{4}x = 3

We expand to get:

\frac{3}{4} x + 3 -  \frac{1}{4}x = 3

We group similar terms to get:

\frac{3}{4}x -  \frac{1}{4}x = 3 - 3

\frac{1}{2}x = 0

x = 0

Put x=0 in to the first equation to get:

y = 6

Therefore the solution is (0,6)

3 0
3 years ago
Read 2 more answers
Hello any help here?
natima [27]
I sorry I don’t know this one
4 0
2 years ago
Which values of x would make a polynomial equal to zero if the factors of the polynomial were (x+3) and (x+12)
Alex Ar [27]

Answer:

A product of factors is zero if and only if one or more of the factors is zero.  That is, if ab = 0, then either a = 0 or b = 0 (or both).

Hence (x+3)(x+12) = 0 only if (x+3) = 0 or (x+12) = 0 or both.  (x+3) = 0 when x = 3.(x+12) = 0 when x = 12.

Hence the values of x that make (x+3)(x+12) = 0 are x = 3 and x = 12.

3 0
3 years ago
Read 2 more answers
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