Answer:
- 1/64 (x+4)² (x-3) (x-4) = 0
Step-by-step explanation:
f(x) = a (x+4)²(x-3)(x-4) ... curve touch (-4,0) and not cross x axis
x=0 f(x) = -3
a (4)² * (-3) * (-4) = -3
a = - 1/64
- 1/64 (x+4)² (x-3) (x-4) = 0
Complete the equation: 43 in =ft .
2 answers:
You might be interested in
In this question, we have to write the set of points from -6 to 3 but excluding -2 and 3 as a union of intervals .
For union, we use U.
For the points that we have to exclude , we put parenthesis on there side that is ().
Therefore the required interval form is
As we see that () are used with -2 and 3 . And that's the required interval form .