Answer:
600 minutes
Step-by-step explanation:
If we write both situations as an equation, we get:
y1 = 24 + 0.15x
<em>y1 </em><em>:</em><em> </em><em>total </em><em>cost </em><em>paid </em><em>in </em><em>first </em><em>plan</em>
<em>x </em><em>:</em><em> </em><em>total minutes </em><em>of </em><em>calls</em>
y2 = 0.19x
<em>y2 </em><em>:</em><em> </em><em>total </em><em>cost </em><em>in </em><em>second </em><em>plan</em>
<em>x:</em><em> </em><em>total </em><em>min</em><em>utes </em><em>of </em><em>call</em>
We are now looking for the situation where the total cost in the two plans is equal, so
y1 = y2
this gives
24 + 0.15x = 0.19x
<=> 0.04x = 24
<=> x = 600
Answer:
im sorry im not sure if its corrrect but its the first one believe which is y=3/5x
Step-by-step explanation:
dont come for me if im wrong
Answer:
-2 (x + 3z) + 4x - 3y + 2z
-2x-6x+4x-3y+2z
2x-4z-3y
hope it helps...
have a nice day!
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Let s = northbound train
Then
2s = southbound train
:
Distance = time * speed
4s + 4(2s) = 600
:
4s + 8s = 600
:
12s = 600
:
s = 600/12
:
s = 50 mph is the northbound train
Then
2(50) = 100 mph is the southbound train
:
:
Check:
4(50) + 4(100) = 600
