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2 years ago

PLEASE PLEASE HELP ME!!!!!! DO NOT DO IT FOR POINTS! I GENUINELY NEED HELP!

Mathematics

1 answer:

vova2212 [387]2 years ago

7 0

Answer:

1. Expression can be rewritten as $5pq$ and $-m+4$

2. The expression for total cost for a visit = $\$10.50+ \$3.2n$ and the Total Cost to visit the fair for 20 tickets is $\$80.50$

3. B. $-x+8$

Step-by-step explanation:

1. Solving for first Question

Given expression are $8pq-3pq$ and $2m-3m+4$

Solving equation we get,

$8pq-3pq=5pq\\2m-3m+4=-m+4$

Expression can be rewritten as $5pq$ and $-m+4$

2. Solving for 2 Question

Given

Fixed cost of carnival = $\$ 10.50$

Additional Cost per ticket for food and ride = $\$ 3.50$

$n$ represents number of tickets.

Total cost to visit carnival = Fixed cost of carnival + Additional Cost per ticket for food and ride $\times$ Number of tickets = $\$ 10.50+\$ 3.50n$

algebraic expression to represent the total cost for a visit to the carnival = $\$ 10.50+\$ 3.50n$

Now Number of tickets sold n = 20

Total cost to visit carnival= $\$ 10.50+\$ 3.50n= \$ 10.50+\$ 3.50\times20= \$ 10.50+\$ 70 =\$ 80.50$

Total Cost to visit the fair for 20 tickets is $\$80.50$

3. Solving for 3 question.

Given :

$\frac{8-4(x-6)}{4}$

Solving Above equation we get:

$\frac{8-4(x-6)}{4}= \frac{4(2-x+6)}{4}=-x+8$

Hence the answer is B. $-x+8$

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profit in year 2017: $y = 405.2\ billion\ dollars$

Step-by-step explanation:

The sales increased from 2 billion dollars to 146 billion dollars in five years, so to find the increase in billion dollars per year, we just need to divide the increase by the amount of time:

$rate\ of\ increase = (146 - 2)/5 = 144 / 5 = 28.8\ billion\ dollars\ per\ year$

To construct a model for these sales, we can use the year 2003 as the initial point of a linear equation:

$y = ax + b$

the variable y will represent the profit in billion dollars, the variable x will represent our time, so we can use (t - 2003) in its place to represent the number of years since 2003 (t is the year we want to calculate), the constant 'a' will be our rate of 28.8, and the constant 'b' is the inicial value for the year 2003, that is, 2 (billions). So we have:

$y = 28.8(t-2003) + 2$

In the year 2017, we would have:

$y = 28.8(2017-2003) + 2$

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3 years ago

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On a coordinate plane, 2 polygons are shown. Polygon A B C D has points (1, negative 6), (5, negative 6), (6, negative 2), and (

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Answer:

The correct option is;

Use a scale factor of 2

Step-by-step explanation:

The parameters given are;

A = (1, -6)

B = (5, -6)

C = (6, -2)

D = (0, -2)

A'' = (1.5, 4)

B'' = (3.5, 4)

C'' = (4, 2)

D'' = ( 1, 2)

We note that the length of side AB in polygon ABCD = √((5 -1)² + (-6 - (-6))²) = 4

The length of side A''B'' in polygon A''B''C''D'' = √((3.5 -1.5)² + (4 - 4)²) = 2

Which gives;

AB/A''B'' = 4/2 = 2

Similarly;

The length of side BC in polygon ABCD = √((6 -5)² + (-2 - (-6))²) = √17

The length of side B''C'' in polygon A''B''C''D'' = √((4 -3.5)² + (2 - 4)²) = (√17)/2

Also we have;

The length of side CD in polygon ABCD = √((6 -0)² + (-2 - (-2))²) = 6

The length of side C''D'' in polygon A''B''C''D'' = √((4 -1)² + (2 - 2)²) = 3

For the side DA and D''A'', we have;

The length of side DA in polygon ABCD = √((1 -0)² + (-6 - (-2))²) = √17

The length of side D''A'' in polygon A''B''C''D'' = √((1.5 -1)² + (4 - 2)²) = (√17)/2

Therefore the Polygon A B C D can be obtained from polygon A''B''C''D'' by multiplying each side of polygon A''B''C''D'' by 2

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