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Gwar [14]
3 years ago
5

PLEASE PLEASE HELP ME!!!!!! DO NOT DO IT FOR POINTS! I GENUINELY NEED HELP!

Mathematics
1 answer:
vova2212 [387]3 years ago
7 0

Answer:

1. Expression can be rewritten as 5pq and -m+4

2. The expression for total cost for a visit = \$10.50+ \$3.2n and the Total Cost to visit the fair for 20 tickets is \$80.50

3.  B.  -x+8

Step-by-step explanation:

1. Solving for first Question

Given expression are 8pq-3pq and 2m-3m+4

Solving equation we get,

8pq-3pq=5pq\\2m-3m+4=-m+4

Expression can be rewritten as 5pq and -m+4

2. Solving for 2 Question

Given

Fixed cost of carnival = \$ 10.50

Additional Cost per ticket for food and ride  = \$ 3.50

n represents number of tickets.

Total cost to visit carnival = Fixed cost of carnival + Additional Cost per ticket for food and ride\times Number of tickets = \$ 10.50+\$ 3.50n

algebraic expression to represent the total cost for a visit to the carnival = \$ 10.50+\$ 3.50n

Now Number of tickets sold n  = 20

Total cost to visit carnival= \$ 10.50+\$ 3.50n= \$ 10.50+\$ 3.50\times20= \$ 10.50+\$ 70 =\$ 80.50

Total Cost to visit the fair for 20 tickets is \$80.50

3. Solving for 3 question.

Given :

\frac{8-4(x-6)}{4}

Solving Above equation we get:

\frac{8-4(x-6)}{4}= \frac{4(2-x+6)}{4}=-x+8

Hence the answer is  B.  -x+8

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42=7(z-3)

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2 years ago
A fair coin is tossed three times and the events A, B, and C are defined as follows: A: \{ At least one head is observed \} B: \
Yanka [14]

Answer:

a) P(A)=0.875

b) \text{P(A or B)}=0.875

c) \text{P((not A)  or B  or (not C))}=0.625

Step-by-step explanation:

Given : A fair coin is tossed three times and the events A, B, and C are defined as follows: A: At least one head is observed, B: At least two heads are observed, C: The number of heads observed is odd.

To find : The following probabilities by summing the probabilities of the appropriate sample points ?

Solution :

The sample space is

S={HHH,HHT,HTT,HTH,TTT,TTH,THH,THT}

n(S)=8

A: At least one head is observed

i.e. A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

n(A)=7

B: At least two heads are observed

i.e. B={HHH,HTT,TTH,THT}

n(B)=4

C: The number of heads observed is odd.

i.e. C={HHH,HTT,THT,TTH}

n(c)=4

a) Probability of A, P(A)

P(A)=\frac{n(A)}{n(S)}

P(A)=\frac{7}{8}

P(A)=0.875

b) P(A or B)

Using formula,

\text{P(A or B)}=P(A)+P(B)-\text{P(A and B)}

\text{P(A or B)}=\frac{n(A)}{n(S)}+\frac{n(B)}{n(S)}-\frac{\text{n(A and B)}}{n(S)}

\text{P(A or B)}=\frac{7}{8}+\frac{4}{8}-\frac{4}{8}

\text{P(A or B)}=\frac{7}{8}

\text{P(A or B)}=0.875

(c) P((not A)  or B  or (not C))

A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

not A = {TTT} = 1

B={HHH,HTT,TTH,THT}

C={HHH,HTT,THT,TTH}

not C = {HHT,HTH,THH,TTT} = 4

So, not A or B or not C = {HHH,HHT,HTH,THH,TTT}=5

\text{P((not A)  or B  or (not C))}=\frac{5}{8}

\text{P((not A)  or B  or (not C))}=0.625

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3 years ago
Exercise 1: Which of the following is not an equation
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