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Setler [38]
2 years ago
12

3^2 x 3^-5 and explain

Mathematics
2 answers:
Alexeev081 [22]2 years ago
6 0

Answer:

0.03703703703

Step-by-step explanation:

sorry bro can't explain

mariarad [96]2 years ago
5 0

Answer:

1/4782969

Step-by-step explanation:

3^2 x 3x^-5=

3^2/1 x 1/3^5=

1/9^7=

1/4782969

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What two integers have a product of -35 and a sum -2
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-7 and 5. The product would be -35 and the sum -2.

Hope this helps

8 0
3 years ago
you deposit 100$ each month into an account earning 8% interest compounded monthly. How much will you have in the account in 15
pickupchik [31]
Use the exponential function of f(x)= 100x times (1.08)^2
7 0
3 years ago
Use the exponential decay​ model, Upper A equals Upper A 0 e Superscript kt​, to solve the following. The​ half-life of a certai
Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

A=A_0 e^{kt}

Where,

A_0 = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = \frac{A_0}{2},

i.e.

\frac{A_0}{2}=A_0 e^{19k}

\frac{1}{2} = e^{19k}

0.5 = e^{19k}

Taking ln both sides,

\ln(0.5) = \ln(e^{19k})

\ln(0.5) = 19k

\implies k = \frac{\ln(0.5)}{19}\approx -0.03648

Now, if the substance to decay to 78​% of its original​ amount,

Then A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0

0.78 A_0=A_0 e^{-0.03648t}

0.78 = e^{-0.03648t}

Again taking ln both sides,

\ln(0.78) = -0.03648t

-0.24846=-0.03648t

\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0
3 years ago
Jose is 40 years old and has had a retirement portfolio for 15 years. He still has about 27 years to go before retirement. Which
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Remember: higher risk means you wait less time to get more money.
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5 0
3 years ago
Read 2 more answers
Ms. Cruz has a tank with 11 fish. After buying two more, she has 2 less than triple the amount of fish Ms. Montesinos has. How m
exis [7]

Answer:

a) Write a let statement below to define your variable(s):

Let the number of fishes Ms. Montesinos has be represented by = f

b) Set up an equation using the variable you defined in (a):

The equation is :

3f - 2 = 13

c) Solve your equation & Check. How many fish does Ms. Montesinos have?

Ms. Montesinos has 5 fishes

Step-by-step explanation:

Ms. Cruz has a tank with 11 fish. After buying two more, she has 2 less than triple the amount of fish Ms. Montesinos has. How many fish does Ms. Montesinos have in her tank?

a) Write a let statement below to define your variable(s):

Let the number of fishes Ms. Montesinos has be represented by = f

b) Set up an equation using the variable you defined in (a):

We are told in the question:

Ms. Cruz has a tank with 11 fish. After buying two more, she has 2 less than triple the amount of fish Ms. Montesinos has.

Therefore,

3× f - 2 = 11 + 2

The equation is :

3f - 2 = 13

c) Solve your equation & Check. How many fish does Ms. Montesinos have?

Solving the above equation:

3f - 2 = 13

3f = 13 + 2

3f = 15

Divide both sides by 3

3f/3 = 15/3

f = 5

Hence, Ms. Montesinos has 5 fishes

4 0
2 years ago
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