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never [62]
3 years ago
14

If two circles are congruent are the diameters the same lengh

Mathematics
2 answers:
sergey [27]3 years ago
6 0
Yes.
The definition of congruent circles is two circles with equal radii. Because the diameter is twice the radius, it is true that the diameters of two congruent circles are the same length.
DanielleElmas [232]3 years ago
5 0
Yes. congruent means same in length and shape. if 2 circles are congruent, they mean that they have the same diameters. if not then they're not congruent.
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How do i do this question ........................,,,,
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You equal each to zero, so -6,0,3,7

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What are the next 2 numbers in the pattern 1, 4, 9, 16, 25, 36, 49, . . .
GREYUIT [131]
This pattern is adding the next odd number, starting with 3. For example, we can use the first few numbers:
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Read 2 more answers
Please help! I will mark brainliest! No random answers please
enot [183]

Answer:

yes

Step-by-step explanation:

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When engaging in weight-control (fitness/fat burning) types of exercise, a person is expected to attain about 60% of their maxim
Nimfa-mama [501]

Answer:

a) <em> standard error of the mean =10.06</em>

<em>b)  The margin of error  = 17.3982</em>

<em>c) 95% of confidence intervals are </em>

<em></em>(89.6018 ,124.3982)<em></em>

<em>d) Lower limit of 95% of confidence interval  = 89.6018</em>

<em>upper limit of 95% of confidence interval  = 124.3982</em>

<em>The Population mean is lies between in these intervals</em>

<u>Step-by-step explanation:</u>

<u><em>Step(i)</em></u><u>:-</u>

Given sample size 'n' = 20

Given sample mean was found to be 107 bpm with a standard deviation of 45 bpm.

<em>Sample mean             </em>x^{-} = 107 bpm<em></em>

<em>Sample standard deviation (S) = 45 bpm</em>

<em>a) standard error of the mean is determined by</em>

<em>     </em>S.E = \frac{S}{\sqrt{n} } = \frac{45}{\sqrt{20} }<em></em>

<em>     S.E = 10.06</em>

<em>b) The margin of error is determined by</em>

<em></em>M.E = \frac{t_{\alpha } X S }{\sqrt{n} }<em></em>

<em>The degrees of freedom  ν   </em>= n-1 =20-1=19<em></em>

<em>   </em>t_{\alpha } = 1.729  

<em></em>M.E = \frac{1.729X 45}{\sqrt{20} }<em></em>

<em></em>M.E = \frac{77.805 }{4.472 } = 17.3982<em></em>

<em>c) 95% of confidence intervals are determined by</em>

<em></em>(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-} + t_{\alpha } \frac{S}{\sqrt{n} } )<em></em>

<em></em>(107 -  1.729\frac{45}{\sqrt{20} } , 107 + 1.729\frac{45}{\sqrt{20} } )<em></em>

<em></em>(107 -  17.3982 } , 107 +17.3982 )<em></em>

<em></em>(89.6018 ,124.3982)<em></em>

<em>d)  </em>

<em>Lower limit of 95% of confidence interval  = 89.6018</em>

<em>upper limit of 95% of confidence interval  = 124.3982</em>

<em>The Population mean is lies between in these intervals</em>

<em></em>

<em></em>

4 0
3 years ago
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