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const2013 [10]
3 years ago
14

In 2017, the population of a village was 7500. In 2019, the population of the village was 8265. Work out the percentage increase

in the population of the village from 2017 to 2019. ​
Mathematics
1 answer:
Sindrei [870]3 years ago
4 0

Answer:

10.2%

Step-by-step explanation:

The given population of the village in 2017 = 7,500

The given population of the village in 2019 = 8,265

The percentage increase in the population of the village from 2017 to 2019 is given by the following percentage increase formula;

Percentage \ increase = 100 \times \dfrac{Final \ value - Initial\ value}{Initial \ value}

The final value of the population in 2019 = 8,265

The initial value of the population in 2017 = 7.500

Therefore;

Percentage \ increase \ in \ the \ population = 100 \times \dfrac{8,265 - 7,500}{7,500} = 10.2 \%

The percentage increase in the population = 10.2%

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An athletic league does drug testing of its athletes, 10 percent of whom use drugs. This test, however, is only 95 percent relia
Vera_Pavlovna [14]

Answer:

0.6786

0.3214

1 / 172

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Step-by-step explanation:

Note: The tree diagram is attached below.

a) The athlete is a drug user, given that the test is positive P(D/+)

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b) The athlete is not a drug user, given that the test is positive P(D' / + )

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c) The athlete is a drug user, given that the test is negative P (D / - )

Using conditional Probability:

P ( D / - ) = P ( D and - ) / P (-)

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= 1 / 172

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(d) The athlete is not a drug user, given that the test is negative P (D' / - )

Using conditional Probability:

P ( D' / - ) = P ( D' and - ) / P (-)

= (0.9 * 0.95) / (0.9 * 0.95 + 0.1*0.05)

= 171 / 172

Answer: P ( D / - ) = 171 / 172

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