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lorasvet [3.4K]
3 years ago
5

What is the common ratio of 2, 10/3, 50/9

Mathematics
1 answer:
mojhsa [17]3 years ago
6 0

The common ratio of 2, 10/3, 50/9 is \frac{10}{6}

<u>Solution:</u>

Given, series of elements are 2, \frac{10}{3}, \frac{50}{9}

We have to find the common ratio of the above given series.

We know that, common ratio of an G.P is division of any number in that series with the previous number of the series.

So, now take \frac{10}{3} and 2

\text { Then, common ratio }=\frac{\frac{10}{3}}{2}

\begin{array}{l}{\text { Common ratio }=\frac{10}{3} \times \frac{1}{2}} \\\\ {\text { Common ratio }=\frac{10}{3 \times 2}=\frac{10}{6}}\end{array}

Hence, the common ratio of the given series is \frac{10}{6}

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Sergio039 [100]

Answer:

<h2>x = 2, y = 3 → (2, 3)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}10x-7y=-1\\-2x-7y=-25&\text{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}10x-7y=-1\\2x+7y=25\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad12x=24\qquad\text{divide both sides by 12}\\.\qquad x=2\\\\\text{Put it to the second equation}\\2(2)+7y=25\\4+7y=25\qquad\text{subtract 4 from both sides}\\7y=21\qquad\text{divide both sides by 7}\\y=3

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4 years ago
5×12÷[-12÷{15+(4-13)}]​
Elina [12.6K]

Answer:

=5×12÷[-12÷{15+(-9)}]

=5×12÷[-12÷6]

=5×12÷(-2)

=-30

Step-by-step explanation:

8 0
3 years ago
After t seconds, a ball tossed in the air from the ground level reaches a height of h feet given by the equation h = 144t-16t^2
lesantik [10]
144t-16t^2= 16t(9-t)
after 3 seconds (just substitute t=3):
16(3)(9-3)=
16(3)(6)=
16*18=
288
maximum height: find the average of the roots:
the roots of 16t(9-t) are t=0 or t=9
since it's a parabola, the maximum is at t=4.5, at 324 ft
if its height is 224 feet, the equation is 224=144t-16t^2
16t^2-144t+224=0
divide by 16: t^2-9t+14=0
this can be factored as (t-2)(t-7)=0
the roots are t=2 and t=7, so the ball has been in the air for either 2 seconds or 7 seconds
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4 0
4 years ago
Read 2 more answers
There are two boxes containing red and blue balls. For box A, there are 3red balls and 7blue balls. For box B, there are 6red ba
Brums [2.3K]

Answer:

0.3333 = 33.33% probability that this red ball is from box A.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Red ball

Event B: From box A.

Probability of a red ball:

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P(A) = 0.3*0.5 + 0.6*0.5 = 0.45

Probability of a red ball from box A:

0.3 of 0.5, so:

P(A \cap B) = 0.3*0.5 = 0.15

What is the probability that this red ball is from box A?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.15}{0.45} = 0.3333

0.3333 = 33.33% probability that this red ball is from box A.

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Answer: 1.5

Step-by-step explanation:

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