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3 years ago

Given: a=b+2c, b=3c. What is the average of numbers a, b and c?

Mathematics

1 answer:

Westkost [7]3 years ago

5 0

Answer:

Step-by-step explanation:

$average = \frac{a + b + c}{3}$

Substitute a= b +2c:

$\frac{a + b + c}{3} = \frac{b + 2c + b + c}{3} \\ \frac{a + b + c}{3} = \frac{2b + 3c}{3}$

Substitute b= 3c:

$\frac{a + b + c}{3} = \frac{2(3c) + 3c}{3} \\ \frac{a + b + c}{3} = \frac{6c + 3c}{3} \\ \frac{a + b + c}{3} = \frac{9c}{3} \\ \frac{a + b + c}{ 3} = 3c$

Thus, the average of the 3 numbers is 3c.

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3 years ago

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Step 1:
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Step 2:

Deal with the terms in 'x' and the constant terms
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Step 3:

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Step 4:

Use the product rule on the term in 'x' and 'y'
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Step 5:

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