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sasho [114]
3 years ago
9

Given: a=b+2c, b=3c. What is the average of numbers a, b and c?

Mathematics
1 answer:
Westkost [7]3 years ago
5 0

Answer:

3c

Step-by-step explanation:

average =  \frac{a + b + c}{3}

Substitute a= b +2c:

\frac{a + b + c}{3}  =  \frac{b + 2c + b + c}{3}  \\  \frac{a + b + c}{3}  =  \frac{2b + 3c}{3}

Substitute b= 3c:

\frac{a + b + c}{3}   = \frac{2(3c) + 3c}{3}  \\  \frac{a + b + c}{3}  =  \frac{6c + 3c}{3}  \\  \frac{a + b + c}{3}  =  \frac{9c}{3}  \\  \frac{a + b + c}{ 3}  = 3c

Thus, the average of the 3 numbers is 3c.

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A shop sells packs of black pens, packs of red pens and packs of green pens.
olchik [2.2K]

Answer:

85 pens  

Step-by-step explanation:

The computation of the number of green pens sold is shown below;

As the number of black pens, red pens, and green pans is 3:5:6

And, the ratio of sold of black pens, red pens, and green pans is 7:3:4

So, the ratio of pens in a number of pens is

= 3 × 7 : 5 × 3 : 4 × 6

= 21: 15 : 24

= 7: 5 : 8

And, the total of 212 pens are sold

So, the number of green pens sold is

= 8 × 212 ÷ (7 + 5 + 8)

= 85 pens  

4 0
3 years ago
The lines y1 = 2x - 6, y2 = -3x + 4, y3 = -1/2x + 4 intersect to form the sides of a right triangle. Find the perimeter and area
tino4ka555 [31]

The area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

<h3>Determining the perimeter and area of the triangle giving line equation</h3>

In order to determine the area and perimeter of the lines, we will plot the giving lines, determine the point of intersection and then use the Pythagoras theorem to determine the dimension of the right triangle.

The points of intersection of the line are;

(x₁, y₁) = (- 0.4, 5.2),

(x₂, y₂) = (-0.8, 4.4),

(x₃, y₃) = (0, 4)

Determine the base

b² = c² -a²

b = √(-0.8)² + (4 - 4.4)²

b = 2√5 / 5

Determine the height

h = √((- 0.4) - (- 0.8))² + (5.2 - 4.4)²

height = 2√5 / 5

For the hypotenuse

r = √2 · b

r = 2√10 / 5

<h3>Determine the Perimeter and area</h3>

Perimeter = s1+s2+s3

Perimeter = 2√5 / 5 + 2√5 / 5 + 2√10 / 5

Perimeter = (2√10 + 4√5) / 5 units

<u>For the area</u>

area = 1/2* base * height

A = 0.5 · (2√5 / 5) · (2√5 / 5)

A = 2/5 square units

Hence the area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

Learn more on area and perimeter of triangles here: brainly.com/question/12010318

#SPJ1

3 0
1 year ago
PLEASE HELP ME ON THIS ALGEBRA PROBLEM!!!
dexar [7]
<h3><em>y(1)=(-1)3+3x(-1)-(-1)-3</em></h3><h3><em>=-1-3+1-3</em></h3><h3><em>=-6</em></h3><h3><em>y=-6</em></h3><h3><em>x=-1</em></h3>

<em></em>

8 0
3 years ago
Amanda has an envelope that is 2 1/4 inches tall. The envelope is 4 1/3 times as long as it is tall. How long is her envelope?
Sidana [21]

Answer:

its 2 1/2 its width

Step-by-step explanation:

4 0
3 years ago
Can someone please do this please.
Finger [1]

Answer:

72°

Step-by-step explanation:

tan x= PN/OP=95/31

⇒x ≈ 72°

7 0
3 years ago
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