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sasho [114]
2 years ago
9

Given: a=b+2c, b=3c. What is the average of numbers a, b and c?

Mathematics
1 answer:
Westkost [7]2 years ago
5 0

Answer:

3c

Step-by-step explanation:

average =  \frac{a + b + c}{3}

Substitute a= b +2c:

\frac{a + b + c}{3}  =  \frac{b + 2c + b + c}{3}  \\  \frac{a + b + c}{3}  =  \frac{2b + 3c}{3}

Substitute b= 3c:

\frac{a + b + c}{3}   = \frac{2(3c) + 3c}{3}  \\  \frac{a + b + c}{3}  =  \frac{6c + 3c}{3}  \\  \frac{a + b + c}{3}  =  \frac{9c}{3}  \\  \frac{a + b + c}{ 3}  = 3c

Thus, the average of the 3 numbers is 3c.

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2 years ago
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How do you solve: secx=-5/2, tanx&lt;0<br><br> Find all six trig functions
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Answer:

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Step-by-step explanation:

During the problem, secx = -5/2, we can assume that as cos = -2/5. -2 = x. 5 = r. find for Y with: x^2+y^2=r^2. After that, plug in for the variables and you get all the answers. Rationalize the square roots, don't forget.

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2 years ago
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3 0
2 years ago
Read 2 more answers
Please answer fast will make you brainlest
quester [9]

Answer:

the correct answer would be left 7

Step-by-step explanation:

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I hope this helps

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