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2 years ago

Given: a=b+2c, b=3c. What is the average of numbers a, b and c?

Mathematics

1 answer:

Westkost [7]2 years ago

5 0

Answer:

Step-by-step explanation:

$average = \frac{a + b + c}{3}$

Substitute a= b +2c:

$\frac{a + b + c}{3} = \frac{b + 2c + b + c}{3} \\ \frac{a + b + c}{3} = \frac{2b + 3c}{3}$

Substitute b= 3c:

$\frac{a + b + c}{3} = \frac{2(3c) + 3c}{3} \\ \frac{a + b + c}{3} = \frac{6c + 3c}{3} \\ \frac{a + b + c}{3} = \frac{9c}{3} \\ \frac{a + b + c}{ 3} = 3c$

Thus, the average of the 3 numbers is 3c.

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Luden [163]

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Step-by-step explanation:

Greetings !

simplify for variable y first

apply exponent rule

$a {}^{b} .a {}^{c} = a {}^{b +c \\ } \\ y {}^{ - 8}y {}^{5} = y {}^{ - 8 + 3}$

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$= y {}^{5}$

Apply exponent rule

$a {}^{ - b} = \frac{1}{a {}^{b} }$

Thus,

$y {}^{ - 5} = \frac{1}{y {}^{5} }$

secondly, simplify for the variable x

Apply exponent rule as we made on y

$x {}^{ - 2}$

$x {}^{ - 2} = \frac{1}{x {}^{2} }$

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Hope it helps!

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Answer:

Step-by-step explanation:

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Citrus2011 [14]

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