Answer: They deleted meh acc for no reason
Step-by-step explanation:
Answer:Rocket Launch A toy rocket is launched straight up in the air from level ground. The distance (in ft) the rocket is above the ground (the position function) is <em>f (t) = 170t -16t2 at any time t (in sec) . Find </em>
Step-by-step explanation:
Answer:
The area of the shape after it has been enlarged by
scale factor 2 will be: 10 cm²
Step-by-step explanation:
The Area is basically a measure of how much space in square units there is inside an object.
As the shape is shown on the centimeter grid.
- The shape clearly occupies the space of 5-centimeter squares.
We also know that If the scale factor > 1, the image is enlarged.
As we know to determine the area of the shape after it has been enlarged by scale factor 2, all we need to do is to multiply the area of the original shape by 2.
The area of original shape = 5 cm²
The area of the shape after the dilation by a scale factor 2 = 5 × 2 = 10 cm²
Thus, the area of the shape after it has been enlarged by
scale factor 2 will be: 10 cm²
Answer:
The rate of change in the submarine's elevation is 26.0 feet per second.
Step-by-step explanation:
She begins 151 feet below sea level
Thus, her initial point is y₁ = 151 feet below sea level
i.e. at t₁=0 seconds, y₁ = 151 feet below sea level
After descending for the 3 seconds, she is 229 feet below sea level.
Thus, her second point is y₂ = 229 feet below sea level after 3 seconds
i.e. at t₂=3 seconds, y₂ = 229 feet below sea level
The rate of change is basically the slope. Thus, the rate of change can be obtained by taking the slope.
slope = rate of change = (y₂ - y₁)/(t₂ - t₁)
= (229 - 151) / (3 - 0)
= 78/3
= 26.0
Therefore, the rate of change in the submarine's elevation is 26.0 feet per second.
Answer:
210 I Think Is The Answer
Step-by-step explanation:
7 x 6 x 5 = 210
