Answer:
Step-by-step explanation:
hello :
hello :
1) divid by 3 : 27:9= 9/3
2) 9/3 = 3/1
Answer: A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.
Step-by-step explanation:
Since we have given that
Radius of inner circle = 57 ft
As we know the formula for "Circumference of circle":
![Distance=Circumference=2\pi r\\\\Distance=2\times \frac{22}{7}\times 57\\\\Distance=358.28\ Ft](https://tex.z-dn.net/?f=Distance%3DCircumference%3D2%5Cpi%20r%5C%5C%5C%5CDistance%3D2%5Ctimes%20%5Cfrac%7B22%7D%7B7%7D%5Ctimes%2057%5C%5C%5C%5CDistance%3D358.28%5C%20Ft)
Since we have also mentioned that there is 2 feet wide circular track for a camera dolly.
So, Radius of outer circle will be given as
![57+2\\=59\ ft](https://tex.z-dn.net/?f=57%2B2%5C%5C%3D59%5C%20ft)
So, Distance = Circumference is given by
![Distance=2\pi R\\\\Distance=2\times \frac{22}{7}\times 59\\\\Distance=370.85\ ft](https://tex.z-dn.net/?f=Distance%3D2%5Cpi%20R%5C%5C%5C%5CDistance%3D2%5Ctimes%20%5Cfrac%7B22%7D%7B7%7D%5Ctimes%2059%5C%5C%5C%5CDistance%3D370.85%5C%20ft)
Hence, Difference between the outer rail travel than a wheel on the inner rail travel is given by
![370.85-358.28\\\\=12.57\ ft](https://tex.z-dn.net/?f=370.85-358.28%5C%5C%5C%5C%3D12.57%5C%20ft)
Therefore, A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.