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steposvetlana [31]
4 years ago
7

Can someone help me solve this please do I use sin cos or tan?

Mathematics
2 answers:
kirza4 [7]4 years ago
8 0
X = √3 * ( 1 / cos(60°) ) = 2√3
y = √3 * tan(60°) = 3

hope I helped.
Roman55 [17]4 years ago
4 0
The answer is 2<span>√ 3 = 3</span>
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Find the product for 1.29 x 5.4<br><br> show work please &lt;3.
Afina-wow [57]

Answer:

6.966

Step-by-step explanation:

•Mark how many you have in the d.p

•If there is two or more add them up

•Multiply like normal given numbers

•Write where the decimal point is to be

Hope that helps

4 0
3 years ago
Read 2 more answers
pls help!? with all 4 Questions I would rlly appreciate your help thx to plp who help me I will improve on my math and be way be
aliina [53]
7.6=w/12
w=7.6(12)
w=91.2

x/2=20
x=20(2)
x=40

8.3x=41
x=41(8.3)
x=340.3

54=r/3
r=54(3)
r=162








6 0
4 years ago
Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact
scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

<em>H</em>₀: The variance of speeds does not exceeds 75 (mph)², i.e. <em>σ</em>² ≤ 75.

<em>Hₐ</em>: The variance of speeds exceeds 75 (mph)², i.e. <em>σ</em>² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}

    =\frac{(55-1)\times 94.7}{75}\\\\=68.184

The test statistic value is, 68.184.

Decision:

cal.\chi^{2}=68.184

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

7 0
3 years ago
Whats 5578 ÷ 68 equal to
kramer

5578/68=82.029411764705882352941176470588

that would be rounded  to 82.02 which is the answer

7 0
3 years ago
Read 2 more answers
The area of a football field can be calculated
pashok25 [27]
360 ft * 160ft = 57,600 ft squared 

I'm not sure, this question was kind of confusing
5 0
3 years ago
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