Answer:
Step-by-step explanation:
Given: In a parallelogram ABCD, diagonals intersect at O and ar(ABCD) is 
.
We need to find the area of triangle AOB.
We know that each diagonal divide the parallelogram in two equal parts and diagonals bisect each other.
It means both diagonals divide the parallelogram in 4 equal parts.
Hence, the values of ar(AOB) is .
Answer: the 32nd term is - 3
Step-by-step explanation:
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + d(n - 1)
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = 15.6
d = 15 - 15.6 = 14.4 - 15 = - 0.6
n = 32
The explicit formula for the arithmetic sequence is
Tn = 15.6 - 0.6(n - 1)
We want to determine the value of the 32nd term, T32. Therefore,
T32= 15.6 - 0.6 (32 - 1)
T32 = 15.6 - 18.6
T32 = - 3
Supplementary angles , when added, = 180
complimentary angles, when added, = 90
< AQC + < GQC = 180.....supplementary
< BQD + < DQE = 90.......complimentary
< CQE + < EQF = 90.......complimentary
< GQF , < FQE.....neither
< BQC + < DQC = 90....complimentary
< W and < X are supplementary...
if < W = 37, then < X = (180 - 37) = 143
< S and < T are complimentary
if < S = 64, then < T = (90 - 64) = 26
< C and < D are supplementary
if < C = 83, the < D = (180 - 83) = 97
cant read all of the last one.....but if they are complimentary, and
< U = 41, then the other angle is : (90 - 41) = 49
Answer= 120
Explanation= plugged it into a calculator
