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horrorfan [7]
3 years ago
8

Write the equation of the line that is parallel to the graph of y=-4x -9, and whose y-intercept is 3.

Mathematics
1 answer:
Olin [163]3 years ago
3 0

Answer:

y = -4x +3

Step-by-step explanation:

the only thing you need from the equation is the slope, which is -4

y = -4x +3

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Y-2=4(x-1) use the point slope for each equation
melomori [17]

Slope = 4

Point = (1, 2)

<h2>Explanation:</h2>

Remember you need to post complete questions in order to get precise and good answers. However, I'll assume you need the point and slope of the following line:

y-2=4(x-1)

A line written in Point-Slope form is given by:

y-y_{0}=m(x-x_{0}) \\ \\ \\ Where: \\ \\ Slope:m=4 \\ \\ Point:(x_{0},y_{0})=(1,2)

By using tools, we get the graph in the figure below. As you can see, this line passes through (1, 2) and has a slope:

m=\frac{4}{1}=4

<h2>Learn more:</h2>

Infinitely many solutions: brainly.com/question/13771057#

#LearnWithBrainly

4 0
3 years ago
F(x)=x^2-3x+18 how many distinct real number zeros does f have?
vampirchik [111]

Answer:

None of the distinct real number zeros the function have.

Step-by-step explanation:

Considering the function

f(x)=x^2-3x+18

The zeroes of a function are those values that touches the x-axis. In order to find those values we must

Set  f(x) = 0 in order to find those values

0=x^2-3x+18

\mathrm{Switch\:sides}

x^2-3x+18=0

\mathrm{Solve\:with\:the\:quadratic\:formula}

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-3,\:c=18:\quad x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}

x=\frac{-\left(-3\right)+\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}

x=\frac{3+\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}

As

3+\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}=3+\sqrt{63}i

so

x=\frac{3+\sqrt{63}i}{2\cdot \:1}

x=\frac{3+3\sqrt{7}i}{2}

x=\frac{3}{2}+\frac{3\sqrt{7}}{2}i

Similarly,

x=\frac{-\left(-3\right)-\sqrt{\left(-3\right)^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}:\quad \frac{3}{2}-i\frac{3\sqrt{7}}{2}

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=\frac{3}{2}+i\frac{3\sqrt{7}}{2},\:x=\frac{3}{2}-i\frac{3\sqrt{7}}{2}

BUT, NONE OF THEM ARE REAL NUMBER ZEROS.

Therefore, none of the distinct real number zeros the function have.

5 0
3 years ago
A circle is drawn within a square as shown. What is the best approximation for the area of the shaded region? Use 3.14 to approx
FrozenT [24]

Answer with explanation:

Length of side of Square = 7 cm

Area of Square = (Side)²=7²=49 cm²

Diameter of circle = 7 cm

So, Radius =\frac{7}{2}=3.5 cm

Area of circle = π × (Radius)²

                       =3.14 × (3.5)²

                       = 3.14 × 12.25

                       =  38.465 cm²

Area of shaded Region = Area of Square - Area of Circle

                                        = 49 - 38.465

                                        =  10.535 cm²

                                        =10.54 cm²

Option A

4 0
3 years ago
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PLZ ANSWER QUESTION THX (look at picture)
aksik [14]

Answer:

66

Step-by-step explanation:

I have a lot to do so there won't be a step by step

3 0
3 years ago
Greatest to least please help me
katrin [286]

Answer:

in ascending order

Step-by-step explanation:

a at the top

b

d

c

5 0
3 years ago
Read 2 more answers
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