We have been given that in ΔHIJ, the measure of ∠J=90°, the measure of ∠I=29°, and JH = 88 feet. We are asked to find the length of IJ to the nearest tenth of a foot.
First of all, we will draw a right triangle using our given information as shown in the attachment.
We can see that in triangle HIJ, the side IJ is adjacent side to angle I and JH is opposite side to angle I.
We know that tangent relates opposite side of right triangle to adjacent side.
Upon rounding to nearest tenth, we will get:
Therefore, the length of the side IJ is approximately 258.8 units.
Answer:
q>=2
Step-by-step explanation:
if she has 3 out of 7 correct she only needs 2 more right. 70% of 7 needs to be 5 or more 5-3=2
The easiest way would be to graph both of them on a coordinate plane. You can either use one online or on your own. When you do graph them, it shows the two lines ARE parallel. I hoped i could help you. Plz mark as brainlies im almost at 5 brainliest so plz mark as brainliest. Thank you very much!
The first number is the X coordinate and the second number is the Y coordinate.
Looking left to right the lines intersect at X = 1
Looking up and down they intersect at Y = -3
The answer is C. (1,-3)
400x is the answer tell me if im right
