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Mumz [18]
3 years ago
13

I need to know what 1/5(6+3+1). And whatever is in the parentheses is to the second power

Mathematics
2 answers:
Inga [223]3 years ago
8 0

Answer:

20

Step-by-step explanation:

1/5(6+3+1)^2

PEMDAS says parentheses first

1/5(10)^2

Then exponents

1/5 *100

Then multiply

20

Natalija [7]3 years ago
4 0

Answer:

\Huge \boxed{\mathrm{20}}

Step-by-step explanation:

\Rightarrow \displaystyle \frac{1}{5} \cdot (6+3+1)^2

Solve for the brackets or parenthesis first.

Adding the terms in the brackets or parenthesis.

\Rightarrow \displaystyle \frac{1}{5} \cdot (10)^2

Solving for the exponent or power.

\Rightarrow \displaystyle \frac{1}{5} \cdot (100)

Multiplying both terms.

\displaystyle \Rightarrow \frac{100}{5} \\ \\ \\ \\  \Rightarrow  20

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It is not a function with domain as { 9 / 2 , 0} and range as {1 / 4, -4, 6}.

We are given a relation:

{(9 / 2, 1 / 4),(4 1 / 2, -4),(0, 5 / 6)}

We can also write it as:

{(9 / 2, 1 / 4),(9 / 2, -4),(0, 5 / 6)}

The domain of the relation will be:

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The range of the relation will be:

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We know that every function can be a relation but every relation cannot be a function.

A relation means the connection between the input and the output.

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Here, this relation is not a function because:

The input 9 / 2 has 2 outputs as 1 / 4 and -4 which is not possible in a function.

Therefore, we get that it is not a function with domain as { 9 / 2 , 0} and range as {1 / 4, -4, 6}.

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