see the picture attached to better understand the problem
we know that
two tangent segments drawn from the same exterior point are congruent
so
JA=JB ,
LA=LC,
KC=KB
JA=13 units
LA=7 units
kC=10 units
hence
perimeter = JA+JB+LA+LC+KC+KB------> 13+13+7+7+10+10------> =60 units
therefore
the answer is
the perimeter of triangle JKL is 60 units
The inside angle for B, which is labeled x is the same as the outside angle of D which is labeled as 72, so we know x = 72.
In a parallelogram two angles next to each other equal 180, so angle A and angle B equal 180.
We know B = 72, so A = 180-72 = 108
Angle A is divided in 2 by angle y, so y = 108/2 = 54
Answers: x = 72
Y = 54
Answer: 233.33.
Step-by-step explanation: Consider marking this answer as brainliest if it helped you out.
We need to solve -3x+4y=12 for x
Let's start by adding -4y to both sides
-3x+4y-4y=12-4y
-3x=-4y+12
x = (-4y+12)/-3
x= 4/3 y -4
Now substitute 4/3 y -4 for x in 1/4 x - 1/3 y =1
1/4 x -1/3 y =1
1/4 (4/3 y -4) -1/3 y =1
Use the distributive property
(1/4)(4/3 y) + (1/4)(-4) -1/3 y =1
1/3 y -1 - 1/3 y =1
Now combine like terms
(1/3y -1/3y) + (-1) =1
= -1
-1 = 1
Now add 1 to both sides
0=2
So there are no Solutions
The answer is C
I hope that's help Will :)
Answer:
there are 11 diffrent sums and the greatest sum is 12
Step-by-step explanation:
