A lighthouse is 15m above sea level.

1 answer:

8 0

For this you will use the tangent function. You have the adjacent side and have to find the opposite side.

tan x = opposite/adjacent
tan 25 = x/15
15 (tan 25) = x
6.9946 = x

So the boat is approximately 6.9946 m away from the lighthouse.

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Find the perimeter of the quadrilateral.

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Question:

Find the perimeter of the quadrilateral. if x = 2 the perimeter is ___ inched.

The complete figure of this question is attached below

Answer:

<h3>The perimeter of the quadrilateral is 129 inches</h3>

Solution:

The complete figure of this question is attached below

Given that, a quadrilateral with,

Side lengths are:

$4x^2 + 8x\ inches \\\\3x^2-5x+20\ inches \\\\7x + 30\ inches \\\\31\ inches$

The values of the side lengths when x = 2 are

$(4x^2+8x)=(4\times 2^2+8\times 2)=(4\times 4+16)=16+16=32\ inch\\\\(3x^2-5x+20)=(3\times 2^2-5\times 2+20)=(3\times 4-10+20)=12+10=22\ inch\\\\(7x+30)=(7\times 2+30)=14+30=44\ inch$