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fredd [130]
3 years ago
8

Given the following linear functions determine the relationship

Mathematics
1 answer:
vovangra [49]3 years ago
6 0

Answer:

  Perpendicular

Step-by-step explanation:

Linear equations will describe parallel lines when the lines have the same slope. These equations are written in slope-intercept form, so we can easily determine that the slopes are ...

  f(x): slope is 5/6

  g(x): slope is -6/5

These are not the same, so the lines are not parallel.

__

The lines will be perpendicular when the product of their slopes is -1. Here, that product is ...

  (5/6)(-6/5) = -30/30 = -1

These equations describe lines that are perpendicular.

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-0.615,-5/8,-0.63 least to greatest
Zarrin [17]
-0.63,-5/8,-0.615 I hope this is helpful and I'm pretty sure it's correct.
4 0
3 years ago
Read 2 more answers
An oval track is made by erecting semicircles on each end of a 44 m by 88 m rectangle. Find the length of the track and the area
Dmitry_Shevchenko [17]

Answer:

The length of the track is 247 m.

The area enclosed by the track is  5391 . 76 sq m.

Step-by-step explanation:

The length of the rectangle  = 88 m

The width of the rectangle  =  44 m

Now, as we know the semicircles are at the end of rectangular track.

So, the diameter of semicircles = Width of the rectangle

⇒ The diameter of the semi circle  = 44 m

⇒Radius of the semi circle  = 44/2 = 22 m

TOTAL LENGTH OF TRACK  

= 2 ( Length of rectangle)  + 2 (Circumference of 1 semicircle)

= 2 x (88 m)  + 2 (\frac{2\pi r}{2})

= 176 m + 2 (3.14)(22 m)  = 176 + 71.08 =  247 m

Hence, the length of the track is 247 m

TOTAL AREA OF TRACK  

= (Area of rectangle)  + 2 (Area of 1 semicircle)

= (Length x Width)  +    2 (\frac{\pi r^2}{2})

=  (44  m x 88 m) +  (3.14)(22 m)(22 m)   = (3872  + 1519.76) sq m

=  5391 . 76 sq m

Hence, the area enclosed by the track is  5391 . 76 sq m.

7 0
3 years ago
Which of the following combinations cannot be the side lengths of a triangle?
Neporo4naja [7]
The sum of the two short legs must be at least as long as the longest leg.

This requirement for a triangle is NOT met by the 2nd selection. Those lengths cannot be a triangle.
8 0
4 years ago
What is the range of the function f(x)=3/4|x|-3
sasho [114]

Range is y\in[-3,+\infty).

Hope this helps.

6 0
4 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
juin [17]

Answer: (B) min = -14, max = -3

<u>Step-by-step explanation:</u>

The minimum is the y-value of the vertex of a positive (U-shaped) parabola. In the graph, the vertex is located at (4.5, -14). The y-value of the vertex is -14.

The maximum is the y-value of the vertex of a negative (∩-shaped) parabola. In the graph, the vertex is located at (1.5, -3). The y-value of the vertex is -3.

8 0
3 years ago
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