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laiz [17]
3 years ago
9

A semicircle has an area of 76.97 squared km. Find it’s radius

Mathematics
1 answer:
shtirl [24]3 years ago
7 0

Answer:

7 km

Step-by-step explanation:

Substitute:

The equation for area of a semi-circle is \frac{r^{2}\pi }{2}

A =  \frac{r^{2}\pi }{2}

76.97 =  \frac{r^{2}\pi }{2}

Multiply by 2 on both sides:

2(76.97) = ( \frac{r^{2}\pi }{2})2

153.94 = r^{2} \pi

Divide by pi on both sides:

153.94 = r^{2} \pi

/pi           /pi

49.03 ≈ r^{2}

Find the square root:

\sqrt{49.03} =\sqrt{r^{2} }

7 = r

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Sedaia [141]
\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
&&  y={{ k }}x
\end{array}\\ \quad \\


and also

\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
&&y=\cfrac{{{  k}}}{x}
\end{array}


now, we know that V varies directly to T and inversely to P simultaneously
thus\bf V=T\cdot \cfrac{k}{P}

so     \bf V=T\cdot \cfrac{k}{P}\qquad 
\begin{cases}
V=42\\
T=84\\
P=8
\end{cases}\implies 42=\cfrac{84k}{8}\implies 4=k
\\\\\\
V=\cfrac{4T}{P}\qquad now\quad 
\begin{cases}
V=74\\
P=10
\end{cases}\implies 74=\cfrac{4T}{10}\implies 185=T
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