1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AleksAgata [21]
3 years ago
7

Solve the equation using the properties of equality: what is the answer

Mathematics
2 answers:
MAVERICK [17]3 years ago
6 0

Answer:

x = 535

Step-by-step explanation:

x/30 - 1/6 = 18

6x - 30/180 = 18

6x - 30 = 18 × 180

6x = 3240 - 30

6x = 3210

x = 3210/6

<em><u>x = 535</u></em>

ahrayia [7]3 years ago
5 0

Answer:

x=545

Step-by-step explanation:

You might be interested in
If f(x)=x2+10sinx, show that there is a number c such that f(c)=1000.
gayaneshka [121]
F(x) is continuous for all x.

Pick a point and show that f(x) is either negative or positive. Pick another point and show that f(x) is negative, if positive, or positive, if negative.

At x = 30, f(30) - 1000 = 900 + 10sin(30) - 1000 ≤ 0
Now, show at another point f(x) - 1000 is positive, and hence, there would be root between 30 and such point.

Let's pick 40.
At x = 40, f(40) - 1000 = 1600 + 10sin(40) - 1000 ≥ 0

Since f(x) - 1000 is continuous, there lies a root between 30 and 40, and hence, 30 ≤ c ≤ 40
7 0
4 years ago
A tennis player wins a match 55% of the time when she serves first and 47% of the time when her opponent serves first. The playe
Ray Of Light [21]

ok so she has a 50% chance of serving first so if she serves first she has a 55% percent chance of winning multiply .55 and .50 to get .275 now she also has a 50% chance of not serving first so multiply .47 and .50 to get .235 now that you have the two probabilities of her winning you add them together so .275+.235 = .51 so she has a <u>51%</u> chance of winning the game
8 0
3 years ago
ON A RECENT MATH TEST MARY SCORED 14 OF 16 CORRECT. JOHN SCORED 23 OF 26AND JOE SCORED 9 OF 11 CORRECT. WHO ACHIEVED THE HIGHER
Andrej [43]

Answer:

I think the answer is mary

7 0
3 years ago
Read 2 more answers
H(t) = −t2 + t + 1 h(x + 1)
Harman [31]

The value of the function h(x + 1) is -x^2 - x + 1

<h3>How to evaluate the function?</h3>

The equation of the function is given as:

h(t) =-t^2 + t + 1

The function is given as:

h(x + 1)

This means that t = x + 1

So, we substitute t = x + 1 in the equation h(t) =-t^2 + t + 1

h(x + 1) =-(x + 1)^2 + (x + 1) + 1

Evaluate the exponent

h(x + 1) =-(x^2 + 2x + 1) + x + 1 + 1

Expand the brackets

h(x + 1) = -x^2 - 2x - 1 + x + 1 + 1

Evaluate the like terms

h(x + 1) = -x^2 - x + 1

Hence, the value of the function h(x + 1) is -x^2 - x + 1

Read more about functions at:

brainly.com/question/1415456

#SPJ1

<u>Complete question</u>

Consider the following function definition, and calculate the value of the function

h(t) = −t2 + t + 1 h(x + 1)

3 0
2 years ago
Can someone please help me?
ahrayia [7]

Answer:

C

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Other questions:
  • Monomials and coefficient
    15·1 answer
  • Plz help it's due tomorrow
    12·1 answer
  • the weight of two boxes of oranges is 186 pounds. one-third of the weight of box A and five-sixths of the weight of box B is 110
    10·1 answer
  • Need help solving this precalculus question. Will mark brainliest
    7·1 answer
  • A company is evaluating which of two alternatives should be used to produce a product that will sell for $35 per unit. The follo
    6·1 answer
  • If f(x)= -2x²-,find f(0).​
    10·1 answer
  • What is the appropriate unit of measure for the mass of a steel cabinet?​
    6·1 answer
  • Plot all points that are a distance of 7 units from 4. What are their values?
    13·1 answer
  • Which expression is the factorization of x2 10x 21? (x 3)(x 7) (x 4)(x 6) (x 6)(x 15) (x 7)(x 14)
    14·1 answer
  • A cylinder has a height of 18 meters and a radius of 18 meters what is the volume
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!