Answer:
1,333
Step-by-step explanation:
Answer:
61
Step-by-step explanation:
Answer:
for part A the answer is B and for part B I think the answer is B too.
The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
Step-by-step explanation:
- To find the E(X) expected value, you come up with the different probabilities for each outcome
- your set of outcomes after 3 tosses would be = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} where H is heads and T is tails
- Each element has a probability of 1/8 so let x represent number of tails
- The E(x)=Summation (x times P(x))
- Now which probability is 1.5 tails? None, so it is either 2 tails or 1 tails
- So you can expect to lose money in 1 game
- But as you play more games the probability of getting 3 tails becomes more and more likely, so you can expect to win in a 100 games