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Fudgin [204]
3 years ago
15

I don't know how to do this and need help please 21y^5+7y^3/7y^6

Mathematics
1 answer:
Rasek [7]3 years ago
7 0

Answer:

Step-by-step explanation:

I am assuming that there are 2 terms in the numerator,

(21y^5+7y^3)/7y^6

= 21y^5/7y^6 + 7y^3/7y^6

= 3/y + 1/y^3.

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