-9x + 4y = 55. –------------- (1)
-11x + 7y = 82. ---------------(2)
Multiply (1) with 7 and (2) with 4. we get
-63x + 28y = 385 ----------(3)
-44x + 28y = 328 ----------(4)
Subtract (4) from (3). you will get
-19x = 57
=> x = 57/(-19)
=> x = -3
Put value of x in (1)
-9×(-3) + 4y = 55
=> 27 + 4y = 55
=> 4y = 55 - 27
=> 4y = 28
=> y = 28/4 = 7
elg=124°
eld=2x
elg+eld=180°=>eld=180°-124°=56°/eld=2x=56°=>x=56°/2=28°
eld+dlh=180°=>dlh=180°-56°=124°
hlg+dlh=180°=>hlg=180°-124°=56°
Answer:
bit.^{} ly/3a8Nt8nStep-by-step explanation:
Answer & Step-by-step explanation:
It really depends on the model. The base can be either a square or a rectangle. The lateral sides can be either squares or rectangles as well, but there will definitely be at least 2 triangular lateral faces.
Answer:
see explanation
Step-by-step explanation:
The angle at the circumference b , is half the angle subtended at the centre by the arc XZ, that is
b = 0.5 × 72 = 36
OZ and OX are congruent ( both radii of the circle )
Thus Δ OXZ is isosceles with base angles congruent, thus
a =
=
= 54
∠ XZY = 90° ( angle in a semicircle is right )