In the figure below, BD and AC are diameters of circle P.

Pls, help. Trigonometry. Please answer in short sentences I'm not picking. Please answer a-i.

padilas [110]

Answer:

a . See attachment

b. because we will find the distance from the bottom of the ladder to the base of the building.

c. sin 60 = opposite side / hypotenuse

d.sin 60 = x / 10

e . 8.66 ft =x

f. see attachment

i. cos 60° = adjacent side / hypotenuse

Step-by-step explanation:

a . See attachment

b. because cos 60° = adjacent side / hypotenuse, the hypotenuse is equal to the length of the ladder (10), and the adjacent side that we will find is the distance from the bottom of the ladder to the base of the building. not the height that the ladder reaches .

c. sin 60 = opposite side / hypotenuse

Because we will find the opposite side which is the height that the ladder reaches.

d.sin 60 = x / 10

e .

0.866025403 = x/10

10 (0.866025403) =x

8.66 ft =x

f. see attachment

i. cos 60° = adjacent side / hypotenuse

Because we will find the adjacent side which is the distance from the bottom of the ladder to the base of the building.

5 0

3 years ago

Between which two values would 75% of the data represented on a box plot lie? Check all that apply.

Inga [223]

Answer:

Hi, everybody, today I'm going to answer this question for you, I took the unit test review, I only got one wrong to be honest, I will tell you which one that was and it's answer, but for now let me answer this question for you. The guy below no offense but you were wrong, the real answer is

the lower quartile and the maximum

the minimum and the upper quartile

I was able to get these two right, and a bonus question with it's own answer.

Mrs. Barnes recorded the grades her students earned on the last chapter test in the frequency table below. The frequency table will be used to make a histogram.

Test Score

Number of Students

31 - 40

1

41 - 50

2

51 - 60

4

61 - 70

6

71 - 80

11

81 - 90

5

91 - 100

4

Which chart has the correct setup for Mrs. Barnes’ histogram?

A 2-column table with 4 rows titled Mrs. Barnes's Histogram. Column 1 has entries interval used, appropriate scale, vertical axis represents, horizontal axis represents. Column 2 has entries 10, 31 to 100, number of students, test scores.

A 2-column table with 4 rows titled Mrs. Barnes's Histogram. Column 1 has entries interval used, appropriate scale, vertical axis represents, horizontal axis represents. Column 2 has entries 10, 0 to 12, number of students, test scores.

A 2-column table with 4 rows titled Mrs. Barnes's Histogram. Column 1 has entries interval used, appropriate scale, vertical axis represents, horizontal axis represents. Column 2 has entries 7, 0 to 12, test scores, number of students.

A 2-column table with 4 rows titled Mrs. Barnes's Histogram. Column 1 has entries interval used, appropriate scale, vertical axis represents, horizontal axis represents. Column 2 has entries 7, 31 to 100, test scores, number of students.

The answer is b, I did a and got it wrong, and it told me the answer is b.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Mr. Dean has an even number of cats and an odd number of dogs. Show how many dogs and cats he might have

kirill115 [55]

1 dog and 2 cats..................................

6 0

3 years ago

Assume that the probability of a defective computer component is 0.02. Components arerandomly selected. Find the probability tha

solmaris [256]

Answer:

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

Step-by-step explanation:

Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.

First six not defective, each with 0.98 probability.

7th defective, with 0.02 probability. So

$p = (0.98)^6*0.02 = 0.0177$