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3 years ago

Solve for K, the constant of variation, in a joint variation problem where y=520, x=5, z=6.5. Solution is?

Mathematics

1 answer:

Luden [163]3 years ago

6 0

Answer:

K = 676

Step-by-step explanation:

When y is directly proportional to x and inversely poportional to z

We have

y = kx/z

When y =520

x = 5

z = 6.5

K =?

We have

520 = k x 5/6.5

Cross multiply

520 x 6.5 = 5k

3380 = 5k

Divide both sides by 5

3380/5 = 5k/5

676 = k

k = 676

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dalvyx [7]

Answer:

Step-by-step explanation:

Slope refers to the steepness of the line.

Slope is equal to change in value of y divided by change in value of x.

The slope of the secant line is given by $\frac{f(x)-f(a)}{x-a}$ .

Given points are $P\left ( 5,-4 \right )\,,\,Q\left ( x,\frac{4}{4-x} \right )$

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(i) At x = 4.9,

$\frac{4}{4.9-4}=\frac{4}{0.9}=4.444444$

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$\frac{4}{4.99-4}=\frac{4}{0.99}=4.040404$

(iii) At x = 4.999,

$\frac{4}{4.999-4}=\frac{4}{0.999}=4.004004$

(iv) At x = 4.9999,

$\frac{4}{4.9999-4}=\frac{4}{0.9999}=4.0004$

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$\frac{4}{5.1-4}=\frac{4}{1.1}=3.636364$

(vi)

At x = 5.01,

$\frac{4}{5.01-4}=\frac{4}{1.01}=3.960396$

(vii) At x = 5.001,

$\frac{4}{5.001-4}=\frac{4}{1.001}=3.996004$

(viii) At x = 5.0001,

$\frac{4}{5.0001-4}=\frac{4}{1.0001}=3.9996$

(b)

Slope of the tangent line is 4.

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3 years ago

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yanalaym [24]

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