Answer:
Is there a picture to it.
that will me helpful for me
Step-by-step explanation:
Willing to help
Step-by-step explanation:
x - 5 < 2 (y - 8) • 1/4
x - 5 < (y - 8) / 2
2 (x - 5) < y - 8
2x - 10 < y - 8
2x - 10 + 8 < y
y > 2x - 2
graph 2x - 2 and shade the section above
<h3>Given</h3>
- ∠AOB = ∠COD = x² -2
- ∠BOC = 2x -10
- ∠AOD = ∠AOB + ∠BOC + ∠COD = 16x +2
<h3>Find</h3>
- x
- the measures of the angles
<h3>Solution</h3>
Substituting the given values of the angles into the given relaion, we get ...
... (x² -2) + (2x -10) + (x² -2) = 16x +2
... 2x^2 -14x -16 = 0 . . . . . subtract the right side (16x+2)
... 2(x +1)(x -8) = 0 . . . . . . .factor
Values of x that satisfy this equation are ...
... x = -1, x = 8
The value x = -1 does not give rise to positive angle values.
For x = 8, the angles are ...
... ∠AOB = ∠COD = 8²-2 = 62
... ∠BOC = 2·8 -10 = 6
... ∠AOD = 16·8 +2 = 130 . . . . = 62 +6 +62
The answer to the question not asked is ...
... x = 8; ∠AOB = ∠COD = 62; ∠BOC = 6; ∠AOD = 130
Dommain is input
range is output from given input (domain)
1,2
just input 1 for x and evaluate
then input 2 for x and evaluate
f(x)=3x
f(1)=3(1)=3
f(2)=3(2)=6
range=(3,6)
f(x)=x^2-2x-5
f(1)=1^2-2(1)-5=1-2-5=-6
f(2)=2^2-2(2)-5=-5
range=(-6,-5)
f(x)=(x+5)x^2
f(1)=(1+5)(1^2)=(6)(1)=6
f(2)=(2+5)(2^2)=(7)(4)=28
range=(6,28)
f(x)=4-x
f(1)=4-1=3
f(2)=4-2=2
range=(3,2)
Answer:
Option B. 
Step-by-step explanation:
we know that
Applying the law of cosines
Let
c------> the missing side length
