The value of 2 in 2,783 is thousand. The value of 2 in 7,283, is hundred.
So it is one times the value.
Answer:
Verified
Step-by-step explanation:
Let the 2x2 matrix A be in the form of:
![\left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
Where det(A) = ad - bc # 0 so A is nonsingular:
Then the transposed version of A is
![A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]](https://tex.z-dn.net/?f=A%5ET%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26c%5C%5Cb%26d%5Cend%7Barray%7D%5Cright%5D)
Then the inverted version of transposed A is
![(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]](https://tex.z-dn.net/?f=%28A%5ET%29%5E%7B-1%7D%20%3D%20%5Cfrac%7B1%7D%7Bad%20-%20cb%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26-c%5C%5C-b%26d%5Cend%7Barray%7D%5Cright%5D)
The inverted version of A is:
![A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]](https://tex.z-dn.net/?f=A%5E%7B-1%7D%20%3D%20%5Cfrac%7B1%7D%7Bad%20-%20bc%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26-b%5C%5C-c%26d%5Cend%7Barray%7D%5Cright%5D)
The transposed version of inverted A is:
![(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]](https://tex.z-dn.net/?f=%28A%5E%7B-1%7D%29%5ET%20%3D%20%5Cfrac%7B1%7D%7Bad%20-%20bc%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26-c%5C%5C-b%26d%5Cend%7Barray%7D%5Cright%5D)
We can see that

So this theorem is true for 2 x 2 matrices
Answer:
1=163 degrees
2=×=10 degrees
3=×=3
Step-by-step explanation:
54x+1+9x-10=180 we are using this expression because alternate angles add up to 180 degrees
54x+9x+1-10=180
63x-9=180
63×=180+9
63×=189
63×÷63×=189÷63×
X=3
Angle in bold print is (54x+1)
54×3=162
162+1=163 degrees
No.2 Find x
7x+35+x+65 =180
7x+x+35×65=180
8x+100=180
8x=180-100
8x=80
8x÷8x=80÷8
X=10 degrees
No.3 Find x
54x+1+9x-10=180
54x+9x+1-10=180
63x-9=180
63x=180+9
63x=189
63x÷63x=189÷63
X=3
I hope I was of help
Step-by-step explanation:
Let a be the price of 1 adult ticket.
Let c be the price of 1 child ticket.
given,

as equation 1,
and

as equation 2.
Now we will solve for a and c using elimination method of simultaneous equations.
Now we multiply equation 2 by 2 to eliminate a and solve for c.

This new equation will be equation 3.
Now we will use equation 1 - equation 3 to eliminate a and solve for c.

Now substitute c into equation 2.

Therefore one adult ticket will cost $17.50 and one child ticket will cost $9.50.