The gradient formula is (y2-y1)/(x2-x1) aka rise/run, where by (x1,y1) and (x2,y2) are two points on the line.
In this case, the gradient
= -5-(-2))/(2-(-2))
= -3/4
Whats the problem you need help with
Given
coordinates of center= (0,9)
Circle passes through (0, 27/2)
Find
Equation of circle
Explanation
The equation of circle in standard form is

We know the circle passes through (0,27/2), then

So the equation in the standard form is

Final Answer
Answer:
f^-1 (x) = (1 - x)/3.
Step-by-step explanation:
f(x) = -3x + 1
3x = 1 - f(x)
x = (1 - f(x)) / 3
So f^-1 x = (1 - x)/3.