(tan(<em>x</em>) + cot(<em>x</em>)) / (tan(<em>x</em>) - cot(<em>x</em>)) = (tan²(<em>x</em>) + 1) / (tan²(<em>x</em>) - 1)
… = (sin²(<em>x</em>) + cos²(<em>x</em>)) / (sin²(<em>x</em>) - cos²(<em>x</em>))
… = -1/cos(2<em>x</em>)
Then as <em>x</em> approaches <em>π</em>/2, the limit is -1/cos(2•<em>π</em>/2) = -sec(<em>π</em>) = 1.
Answer:
its a simple for me
Step-by-step explanation:
2+144 i
Hello there! Shelly ran D) 5/10 more miles than Ben.
To find the difference between the two runner's distances, subtract the smaller distance from the greater distance.
8/10 - 3/10 = 5/10
Since there is a difference of 5/10, this means Shelly ran 5/1 more miles.
I hope this helps, & have a great rest of your day! :)
Answer:
Question (A) firgue b is pallorgram
Question ( B) Only A is a rentengle
Question (C) is already right
Step-by-step explanation:
