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3 years ago

15.12 is what percent of 12?

Mathematics

1 answer:

Llana [10]3 years ago

6 0

Answer:

Step-by-step explanation:

$\bold{METHOD\ 1}\\\\\begin{array}{ccc}15.12&-&p\%\\\\12&-&100\%\end{array}\qquad\text{cross multiply}\\\\\\12p=(15.12)(100)\\12p=1512\qquad\text{divide both sides by 12}\\p=126$

$\bold{METHOD\ 2}\\\\p\%=\dfrac{p}{100}\\\\p\%\ of\ 12\ is\ equal\ to\ 15.12:\\\\\dfrac{p}{100}\cdot12=15.12\\\\\dfrac{12p}{100}=15.12\qquad\text{multiply both sides by 100}\\\\12p=1512\qquad\text{divide both sides by 12}\\\\p=126$

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Please, Find the value of x

dsp73

Answer:

85+(5x-10)=11x+3 (sum of two non-adjacent interior angle is equal to exterior angle )

75+5x=11x+3

75-3=11x-5x

6x=72

x=72/6

x=12

6 0

3 years ago

Which equation could be used to find the height of the flagpole

Sauron [17]

X = height of pole (in meters)

With respect to the 50 degree angle, the side x is the opposite leg. It is the leg furthest from the reference angle. The hypotenuse is 5 meters.

The trig function sine ties together the opposite and hypotenuse

sin(angle) = opposite/hypotenuse
sin(50) = x/5
5*sin(50) = x .... multiply both sides by 5
x = 5*sin(50)

------------------

Since x = 5*sin(50) isn't listed as an answer choice, let's try using cosine. We can't use it right away because we don't know the adjacent side. What we can do is change the reference angle. The missing angle of the triangle is 90-50 = 40 degrees. Let's make the 40 degree angle the reference angle

So x is now the adjacent side with respect to the 40 degree reference angle. The hypotenuse is always the longest side. The hypotenuse stays at 5.

cos(angle) = adjacent/hypotenuse
cos(40) = x/5
5*cos(40) = x
x = 5*cos(40)

This expression is listed. The answer is choice B

4 0

3 years ago

Two dance teams, the Roses and the Tulips, are perfectly matched so that their chances of winning are both set at 50%. What is t

shtirl [24]

Answer:

Step-by-step explanation:

Step 1

The fist step is to define the probabilities.

The events are independent from each other. Each team wins with probability $\frac{1}{2}$ and looses with probability $\frac{1}{2}.$ Let $P(W_R)$ be probability that Roses win and $P(L_R)$ be the probability that Roses loose.

Step 2

The second step is to calculate the probabilities by multiplying the probabilities with the first 3 terms in the product being the probability of a win and the last term being the probability of a loss.

The calculation is shown below,

$P(W_R)\times P(W_R)\times P(W_R)\times P(L_R)=\frac{1}{2} \times \frac{1}{2} \times\frac{1}{2} \times\frac{1}{2} =\frac{1}{16}$

Step 3

The last step is to convert this probability into a percentage. Converting this probability to a percentage is done as shown below,

$\frac{1}{16} \times 100\%=6.25\%.$

Step 4

The next step is to round down the percentage . The value of 6.25% rounded down is 6%. The correct answer is 6%.

3 0

3 years ago

A coin is tossed and an eight-sided die numbered 1 through 8 is rolled. Find the probability of tossing a head and then rolling

ratelena [41]

Answer: 7/8

Step-by-step explanation:

Probability is calculated by number of possible outcomes/ total outcomes

From the question, a coin only has two sides, Head or Tail. Total outcomes is therefore equal to 2

Possible outcome is to toss a head, which is one event

Probability of tossing a head is therefore =1/2

The second part of the question is rolling a die with eight sides.

Here, the die is said to have eight sides, 1,2,3,4,5,6,7,8. Total outcomes is therefore equal to 8

Possible outcome of rolling a number greater than 5 is 3 possibilities, that is rolling 6, 7 and 8.

Pr(rolling > 5) is 3/8

Therefore, Pr ( head; rolling > than 5)

= 1/2 + 3/8

=7/8

I hope this is clear, please mark as brainliest answer

6 0

3 years ago

manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe

Naddik [55]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32$

he then turns around and grabs that money and sticks it for another 9 years,

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64$

add both amounts, and that's how much is for the whole 21 years.

6 0

3 years ago