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Zielflug [23.3K]
3 years ago
6

At a drag race, the light turns green and 0.00125 hours later, a dragster is traveling 300 miles per hour. Calculate the acceler

ation of the dragster
Mathematics
1 answer:
taurus [48]3 years ago
8 0
The acceleration is 98ft/s ²
Hope I helped!
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Combine like terms to create an equivalent expression -4/7p+(-2/7p)+1/7
STatiana [176]
-6/7p+1/7 um Idk what you wanted me to do but I added -4/7p with -2/7p
7 0
3 years ago
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On Saturday, Lukas drove 4x – 5 miles. On Sunday, he drove 3x – 10 miles. What is the difference in miles driven?
Soloha48 [4]

Answer:

C

Step-by-step explanation:

(4x-5) - (3x-10) = ?

(4x-5) - 1 (3x-10) = ? DISTRIBUTE THE INVISIBLE -1 to (3x-10)

Turns into: 4x - 5 - 3x + 10

Which equals: x + 5

8 0
3 years ago
What is the solution set for 2x+5y>-1 and 4x-3<-3?
bekas [8.4K]

PROBLEM ONE

•

Solving for x in 2x + 5y > -1.

•

Step 1 ) Subtract 5y from both sides.

2x + 5y > -1

2x + 5y - 5y > -1 - 5y

2x > -1 - 5y

Step 2 ) Divide both sides by 2.

2x > -1 - 5y

\displaystyle\frac{2x}{2} > \displaystyle\frac{-1 - 5y}{2}

\displaystyle\ x > \frac{-1 - 5y}{2}

So, the solution for x in 2x + 5y > -1 is...

\displaystyle\ x > \frac{-1 - 5y}{2}

•

Solving for y in 2x + 5y > -1.

•

Step 1 ) Subtract 2x from both sides.

2x + 5y > -1

2x - 2x + 5y > -1 - 2x

5y > -1 - 1x

Step 2 ) Divide both sides by 5.

5y > -1 - 1x

\displaystyle\frac{5x}{5} > \frac{-1 -1x}{5}

\displaystyle\ x > \frac{-1 -1x}{5}

So, the solution for y in 2x + 5y > -1 is...

\displaystyle\ x > \frac{-1 -1x}{5}

•

PROBLEM TWO

•

Solving for x in 4x - 3 < -3.

•

Step 1 ) Subtract 3 from both sides.

4x - 3 < -3

4x -3 - 3 < -3 - 3

4x < 0

Step 2 ) Divide both sides by x.

4x < 0

\displaystyle\frac{4x}{4}

x < 0

So, the solution for x in 4x - 3 < -3 is...

x < 0

•

•

- <em>Marlon Nunez</em>

7 0
3 years ago
Monica deposits $100 into a savings account that pays a simple interest rate of 4.5%, Paul
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Answer:

yes she is correct

Step-by-step explanation:

because in 1 year it will go up 4.5%

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The following formula relates three quantities force mass and acccelerations<br> F=ma
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True.  Dissect "F=ma" and you'll get "Force," "mass" and "acceleration."
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