4x^2y(x+2)-x(xy2-3)
(4x^2y)^(x)+(4x^2y)(2)-x^2y^2+3x
4x^3y+8x^2y-x^2y^2+3x
4x^3y-x^2y^2+8x^2y+3x
This was very confusing to solve so sorry if I’m wrong.Also sorry if it’s too hard to write it.
Answer:
The acceleration is 965 kg•ms^-2
Step-by-step explanation:
Mathematically;
Force = mass * acceleration
From the question;
Force = 1930 N (kg• ms^-2)
mass = 2kg
Acceleration = Force/mass = 1930/2 = 965 ms^-2
Answer: 11/15
Step-by-step explanation:
Log₄8 + 3 · log₄x
so the easiest way to do this is to note that these logs are separated by an addition symbol--it isn't "log₄8 + 3" times "log₄x"
log₄8
plus
3 · log₄x
for the second log, you can condense it with log properties/rules: the coefficient out front, when you condense it, becomes the exponent for the argument of your log:
3 · log₄x = log₄(x³)
so, having condensed that, your equation reads:
log₄8 + log₄(x³)
you could technically evaluate the first log, but the question wants both of these to become a single logarithm, which means you want to combine them. log properties state that if logs are being added, you can multiply their arguments (for example: logₓab = logₓa + logₓb)
you just want to apply that property to this, so you'll be multiplying your arguments 8 and x³:
log₄(8x³) is the answer, expressed as one logarithm.