So I'm assuming that you're taking Calculus.
The first thing you want to do is take the integral of f(x)...
Use the power rule to get:
4X^2-13X+3.
Now solve for X when f(x)=0. This is because when the slope is 0, it is either a minimum or a maximum(I'm assuming you know this)
Now you get X=0.25 and X=3. Since we are working in the interval of (1,4), we can ignore 0.25
Thus our potential X values for max and min are X=1,X=4,X=3(You don't want to forget the ends of the bounds!)
Plugging these value in for f(x), we get
f(1)=2.833
f(3)=-8.5
f(4)=1.667
Thus X=1 is the max and X=3 is the min.
So max:(1,2.833)
min:(3,-8.5)
Hope this helps!
What the hel you expect us to do all that for 5 kids points? Go ask you mom to do that for you. If you're asking US to do that, then it has to be 40 or 50 points.
Y= kx (k being a constant)
10= k × 4 k=5/2
y= 5x/2 The answer is C.
what dou you need?????????
Answer:
f(x) + 2.
Step-by-step explanation:
Example:
If we have say f(x) = x + 1 then 2 units will be added to f(x) when it is moved up 2 units.
So the equation of this line will be f(x) + 2 which in this example is
x + 1+ 2.
The new function is x + 3.
