The weight of the new student is 27 kg.
Average weight
= total weight ÷total number of students
<h3>
1) Define variables</h3>
Let the total weight of the 35 students be y kg and the weight of the new student be x kg.
<h3>2) Find the total weight of the 35 students</h3>
<u>
</u>
y= 35(45)
y= 1575 kg
<h3>3) Write an expression for average weight of students after the addition of the new student</h3>
New total number of students
= 35 +1
= 36
Total weight
= total weight of 35 students +weight of new students
= y +x
<h3>4) Substitute the value of y</h3>
<h3>5) Solve for x</h3>
36(44.5)= 1575 +x
1602= x +1575
<em>Subtract 1575 from both sides:</em>
x= 1602 -1575
x= 27
Thus, the weight of the new student is 27 kg.
First since the perimeter of this problem is P=2b x 2h I first multiplied 26 by 2 and got 52 inches. then I subtracted 52 from 180 and got 128. From there I divide 128 by 2 and I got 64 for the length
600 ft. This is because you travel 10 feet per second and there are 60 seconds in a minute. 10 x 60 =600
Answer:
x = 24
Step-by-step explanation:
The given line y = 3 is a horizontal line with slope zero (0).
We wish to find the equation of a line that is perpendicular to y = 3. Such a line would be a vertical one. Vertical lines do not have slopes defined (due to division by zero).
Thus the general form of the equation of this new line is x = c.
This new line passes through (24, -56). Thus, x must be 24: x = 24
