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2 years ago

If two angles are complements, then they are both acute. Which is the hypothesis?

Mathematics

1 answer:

romanna [79]2 years ago

8 0

Answer:

Both angle are acute

Step-by-step explanation:

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You walk an average of 3.2 miles per hour on the way to school and at an average of 4 miles per hour on the way home the total w

7nadin3 [17]

The answer to this question is:
You walk an average of 3.2 miles per hour on the way to school and at an average of 4 miles per hour on the way home the total walking time is 18 minutes how far away is the school Round your answer to the nearest hundredth of a mile
<span>.53 mi
</span><span>.133 hrs

Hope This Helped, Markadoodle
Your Welcome :)</span>

8 0

3 years ago

Read 2 more answers

Read the following description of a relationship: Anne's shower uses 15 liters of water per minute. Let m represent the number o

ki77a [65]

Answer:

105

Step-by-step explanation:

m= minutes

Minutes*15= Whole water

m*15=w

7*15=105

3 0

3 years ago

90oriX9 un rezultat va rog

bogdanovich [222]

The answer is 333.423 hope this helps u

4 0

3 years ago

Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

$\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx$

Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$

6 0

3 years ago

PLEASE ANSWERRRRRRRRRRRRRRR

hoa [83]

Let $T,S$ be the number of days spent at Tahoe and San Francisco, respectively.

We don't know the values of $T$ and $S$ yet, but we know that the holiday lasted 9 days:

$T+S=9$

We also know that each day spent in Tahoe costed 350 and each day spent in San Francisco costed 475. So, the total cost of the holiday is the sum of the number of days muliplied by their cost:

$350T+475S=3650$

If we put the two equations together, we have the system

$\begin{cases}T+S=9\\350T+475S=3650\end{cases}$

Which yields

$S=4,\quad T=5$

5 0

3 years ago