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Sedbober [7]
3 years ago
13

Question 10: A triangle has two sides that are 10 inches and 15 inches in

Mathematics
2 answers:
mars1129 [50]3 years ago
6 0

Answer:

I think the third side would be 10

Step-by-step explanation:

Amiraneli [1.4K]3 years ago
6 0
The answer is 10 because it is.
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3x(-2x)8(-2)=30 what value of x makes the equation true.<br><br> A. 24<br> B.26<br> C.5<br> D.6
Leokris [45]

Answer:

Step-by-step explanation:

5 0
3 years ago
Find the value of N in the question
iris [78.8K]
N = 1/3 -0
n = 1/3

answer
n = 1/3
8 0
3 years ago
M∠1=119∘ and m∠2=61∘.<br> What is m∠3?
marin [14]

Answer:

m∠3 = 119°

Step-by-step explanation:

All the angles must equal 360° when added together. You have two known angles that are right next to each other. If you add m∠1 and m∠2, 119 + 61, it is equal to 180°. This means that m∠3 and m∠4 must be equal to 180° as well and since there are only two lines, it is safe to assume that opposing angles are the same so m∠1 = m∠3 and m∠2 = m∠4.

4 0
2 years ago
Read 2 more answers
What are the solutions of the quadratic equation (x + 3)2 = 49
Korvikt [17]

the right answer is

x = 4 and x = –10

I just take the test and I got it right I hope yall get it right to


8 0
3 years ago
Read 2 more answers
A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form
Over [174]

Answer:

\vec{v}= \text{ or } \approx

Step-by-step explanation:

Component form of a vector is given by \vec{v}=, where i represents change in x-value and j represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector \vec{v}=, the magnitude is ||v||=\sqrt{i^2+j^2.

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being i, one leg being j, and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}

To find the other leg, i, we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}

Verify that (9\sin 10^{\circ})^2+(9\cos 10^{\circ})^2=9^2\:\checkmark

Therefore, the component form of this vector is \vec{v}=\boxed{}\approx \boxed{}

6 0
3 years ago
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