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2 years ago

Point C' is the image of C (-4,-2)under a reflection across the y-axis.

Mathematics

1 answer:

Furkat [3]2 years ago

8 0

Answer:

The coordinates of point C' are (4, -2)

here's why:

When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is taken to be the additive inverse. The reflection of point (x, y) across the y-axis is (-x, y). So if we use this information with the problem, the original coordinates, (-4, -2), the new coordinates will be (4, -2).

Hope this helped.

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3 years ago

Read 2 more answers

Hi there. I am having trouble with calculating in base 4. The problem is 2014-324=

Arlecino [84]

Answer:

The required answer is $(201)_4-(32)_4=(103)_4$ .

Step-by-step explanation:

Consider the provided numbers:

We need to subtract in base 4.

$(201)_4-(32)_4$

The place value of 201 is:

1 is at units place, 0 is at four's place and 2 is at 4 squared place.

The place value of 32 is:

2 is at units place and 3 is at four's place.

201

- 32

Start subtracting the numbers from the unit place.

Here, we need to subtract 2 from 1, which is not possible so borrow 4 from the four's place but there is 0 at four's place so borrow from 4 squared place and change 2 to 1.

Also change 0 to 4 because we have borrow 4 from squared place.

Now 1 can borrow 4 from the four's place which will become 1+4=5 and change 4 at four's place to 3.

Now the number will look like this:

135

- 32

Now subtract the number as shown.

135

- 32

103

Hence, the required answer is $(201)_4-(32)_4=(103)_4$ .

4 0

3 years ago

A restaurant operator in Accra has found out that during the lockdown,if she sells a plate of her food for Ghc 20 each,she can s

ella [17]

The demand equation illustrates the price of an item and how it relates to the demand of the item.

The slope of the demand function is -1/2
The equation of the demand function is: $R(x) = (300 - 10x) \times (20 + 5x)$
The price that maximizes her revenue is: Ghc 85

From the question, we have:

$Plates = 300$

$Price = 20$

The number of plates (x) decreases by 10, while the price (y) increases by 5. The table of value is:

$\begin{array}{cccccc}x & {300} & {290} & {280} & {270} & {260} \ \\ y & {20} & {25} & {30} & {35} & {40} \ \end{array}$

The slope (m) is calculated using:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

So, we have:

$m = \frac{25-20}{290-300}$

$m = \frac{5}{-10}$

$m = -\frac{1}{2}$

The equation of the demand is as follows:

The initial number of plates (300) decreases by 10 is represented as: (300 - 10x).

Similarly, the initial price (20) increases by 5 is represented as: (20 + 5x).

So, the demand equation is:

$R(x) = (300 - 10x) \times (20 + 5x)$

Open the brackets to calculate the maximum revenue

$R(x) =6000 + 1500x - 200x - 50x^2$

$R(x) =6000 + 1300x - 50x^2$

Equate to 0

$6000 + 1300x - 50x^2 =0$

Differentiate with respect to x

$1300 - 100x =0$

Collect like terms

$100x =1300$

Divide by 100

$x =13$

So, the price at maximum revenue is:

$Price= 20 + 5x$

$Price= 20 + 5 * 13$

$Price= 85$

In conclusion:

The slope of the demand function is -1/2
The equation of the demand function is: $R(x) = (300 - 10x) \times (20 + 5x)$
The price that maximizes her revenue is: Ghc 85