King rewarded the inventor of chess by giving grain of wheat on every square of the chess board. He places one grain of wheat on first square, 2 on second, 4 on 3rd, 8 on 4th and so on.

In fact he places grains of wheat in a progression S = 1, 2, 4, 8, 16.........n terms where value of n is 64.

We can rewrite the progression as S = 2°, 2, 2², 2³,.........n terms (n = 64)

In a geometric progression we know the nth term = $a(r^{n-1})$

where a = first term of the series, r = common ratio, n = number of terms

Now we have to calculate the weight of all wheat placed on 45th square.

So we will put the values in the given formula 45th term =

$1\times (2^{45-1})$ = $2^{44}$ = $1.76\times 10^{13}$

Then the weight of wheat will be = $2.51\times 10^{9}pounds$ = $1.26\times 10^{6}tons$

7 0

3 years ago

Its like a word question?

Sloan [31]

Answer:

-3+x=x+4

Step-by-step explanation:

Pls Mark Brainliest

5 0

4 years ago

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